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2 years ago

When performing dimensional analysis, we usually use conversion factors. What is a conversion factor?

Chemistry

1 answer:

lora16 [44]2 years ago

4 0

Answer:

A conversion factor is a variable that transforms the dimension of one variable into the terms of another variable.

Explanation:

Let be $x$ and $y$ two variables with diferent dimensions (units), $r$ is a conversion if transforms the dimension of one variable into the terms of the other variable. That is:

$y = r\cdot x$ (1)

Where:

$x$ - Input, [input unit]

$y$ - Output, [output unit]

$r$ - Conversion factor, [output unit] per [input unit]

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A hot toluene stream, which has mass flow rate of 8.0 kg/min, is cooled by cooling water in a cocurrent heat exchanger; its temp

Alex Ar [27]

Complete Question

The complete question is shown on the first question

Answer:

a) The duty of the heat exchanger is given as 6.8658 KJ /sec

b) The temperature of the water leaving the exchanger is TOUT = 29.84 ⁰C

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3 years ago

Water comes from different a.levels b.phases c.sources d.stages

bezimeni [28]

Answer:

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Explanation:

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2 years ago

how many molecules of sulfuric acid are in a spherical raindrop of diameter 6.0 mm if the acid rain has a concentration of 4.4 *

Vitek1552 [10]

Answer:

The number of moles =

$Moles=4.97\times 10^{-8}$

The number of molecules =

$Molecules = 2.99\times 10^{16}$

Explanation:

Volume of the sphere is given by :

$V=\frac{4}{3}\pi r^{3}$

here, r = radius of the sphere

$radius=\frac{diameter}{2}$

$radius=\frac{6.0}{2}$

Radius = 3 mm

r = 3 mm

1 mm = 0.01 dm (1 millimeter = 0.001 decimeter)

3 mm = 3 x 0.01 dm = 0.03 dm

r = 0.03 dm

<em>("volume must be in dm^3 , this is the reason radius is changed into dm"</em>

<em>"this is done because 1 dm^3 = 1 liter and concentration is always measured in liters")</em>

$V=\frac{4}{3}\pi 0.03^{3}$

$V=\frac{4}{3}\pi 2.7\times 10^{-5}$

$V=1.13\times 10^{-4}dm^{3}$

$V=1.13\times 10^{-4}L$ (1 L = 1 dm3)

Now, concentration "C"=

$C=4.4\times 10^{-4}moles/liter$

The concentration is given by the formula :

$C=\frac{moles}{Volume(L)}$

This is also written as,

$Moles = C\times Volume$

$Moles=1.13\times 10^{-4}\times 4.4\times 10^{-4}$

$Moles=4.97\times 10^{-8}$ moles

One mole of the substance contain "Na"(= Avogadro number of molecules)

So, "n" mole of substance contain =( n x Na )

$N_{a}=6.022\times 10^{23}$

Molecules =

$Molecule=4.97\times 10^{-8}\times 6.022\times 10^{23}$

$Molecules = 2.99\times 10^{16}$ molecules

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3 years ago

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max2010maxim [7]

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2 years ago

How many grams of o2(g) are needed to completely burn 70.2 g of C3H8(g)

Lubov Fominskaja [6]

First you must write a balanced chemical equation.

C3H8 + 5O2 --> 3CO2 + 4H2O

From there, we can set up the stoichiometry equation to solve.

g O2= 70.2 g C3H8 X (1 mol C3H8/44.0962g C3H8) X (5 mol O2/1 mol C3H8) X (31.998g O2/1 mol O2)

Now solve, and you should get 254.7 g O2. Hope this helped!

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2 years ago