Answer:
The Net reaction is
-

-

-
Explanation:
From the Question we are told that the buffers are
and 
When NaOH is added the Net ionic reaction would be
-

-

-
It's probably animal if that's what's you're asking.
Elements were grouped on their properties and behaviors, so hydrogen resides with the alkali metals in group 1 (1A) because it has only 1 valence electron, like the metals in that group.