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dolphi86 [110]
1 year ago
12

When a piece of metal A is placed in a solution containing ions of metal B, metal B plates out on the piece of A.(a) Which metal

is being oxidized?
Chemistry
1 answer:
zmey [24]1 year ago
5 0

While metal B is being reduced from an ion to a solid metal, metal A is being oxidized.

Metal A is being displaced because, through oxidation, it transforms from a solid metal to ions in a solution.

What is Oxidation ?

Redox reactions include a change in the oxidation state of the substrate. Loss of electrons or a rise in an element's oxidation state are both considered to be oxidation.

Gaining electrons or lowering the oxidation state of an element or its constituent atoms are both examples of reduction.

In general, the term "reduction" refers to a reaction in which a chemical receives additional electrons; the compound that gets electrons is referred to as being reduced. We can think of the transformation of a ketone or an aldehyde into an alcohol as a two-electron reduction because hydride can be thought of as a proton plus two electrons.

So finally we can say that Metal A is being oxidized.

To know more about Oxidation please click here : brainly.com/question/25886015

#SPJ4

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The answer here would be 14.9 %KCl and here is how I can explain why:
33.5g / 225.6g x 100% = 14.9% 
<span>you are looking for % of KCl in the solution, you have to add the mass of the KCl and water to get the total mass of the solution
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7 0
3 years ago
Discuss the separation of solid of different sizes​
mariarad [96]

Answer:

Chromatography involves solvent separation on a solid medium. Distillation takes advantage of differences in boiling points. Evaporation removes a liquid from a solution to leave a solid material. Filtration separates solids of different sizes.

Explanation:

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8 0
2 years ago
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Setler [38]
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7 0
2 years ago
Which metal will spontaneously react with Zn2+(aq), but will not spontaneously react with Mg2+(aq)?
DerKrebs [107]
Correct Answer: option <span>(1) Mn(s)

Reason: 
The </span><span>spontaneity of electrochemical cell, depends on the it's Eo value. Electrochemical cells with positve Eo are spontanous and vice-versa.
</span>
In present case, the  Eo of half-cell of interest are as follows:
Eo Zn2+/Zn = <span>-0.763v
</span>Eo Mg2+/Mg = 2.37v
Eo Mn2+/Mn = -1.18v

Therefore, Eo cell (with Zn as one of the half-cell) =  Eo Zn2+/Zn - Eo Mn2+/Mn
                                                                                =  -0.763 - (-1.18)
                                                                                = 0.417v

On other hand, Eo cell (with Mg as one of the half-cell) =  Eo Mg2+/Zn - Eo Mn2+/Mn
                                                                                =  -2.37 - (-1.18)
                                                                                = -1.19v

Thus, Mn(s) <span>metal will spontaneously react with Zn2+(aq), but will not spontaneously react with Mg2+(aq)</span>
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