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dolphi86 [110]
1 year ago
12

When a piece of metal A is placed in a solution containing ions of metal B, metal B plates out on the piece of A.(a) Which metal

is being oxidized?
Chemistry
1 answer:
zmey [24]1 year ago
5 0

While metal B is being reduced from an ion to a solid metal, metal A is being oxidized.

Metal A is being displaced because, through oxidation, it transforms from a solid metal to ions in a solution.

What is Oxidation ?

Redox reactions include a change in the oxidation state of the substrate. Loss of electrons or a rise in an element's oxidation state are both considered to be oxidation.

Gaining electrons or lowering the oxidation state of an element or its constituent atoms are both examples of reduction.

In general, the term "reduction" refers to a reaction in which a chemical receives additional electrons; the compound that gets electrons is referred to as being reduced. We can think of the transformation of a ketone or an aldehyde into an alcohol as a two-electron reduction because hydride can be thought of as a proton plus two electrons.

So finally we can say that Metal A is being oxidized.

To know more about Oxidation please click here : brainly.com/question/25886015

#SPJ4

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Answer: 581 gmol

0.581 kmol

1.28\times 10^{-3}lbmol

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{50\times 1000g}{86g/mol}=581mol

1. The conversion for mol to gmol

1 mol = 1 gmol

581 mol= \frac{1}{1}\times 581=581gmol

2. The conversion for mol to kmol

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581 mol= \frac{0.001}{1}\times 581=0.581kmol

3. The conversion for mol to lbmol

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