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soldi70 [24.7K]

2 years ago

14

What is the value of y? A. 55° B. 850 C. 10° D. 110°

1 answer:

GaryK [48]2 years ago

5 0

I may not know I am sorry ma’am for your math problem is to hard

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Can you guys help me ?

AysviL [449]

Answer:

C the 12th root of (8^x)

Step-by-step explanation:

This becomes 8 ^ x/4 ^ 1/3

We know that a^b^c = a^ (c*c)

8 ^(x/12)

8 0

3 years ago

Read 2 more answers

A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave

erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, $L$ = 120 cm

Its wavelength $\lambda_1$ = 480 cm

$\lambda_2$ = 160 cm and $\lambda_3$ = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

The fundamental wavelength of a pipe which is open at both ends is 2L.
The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ $4L=4(120)=480\ cm$

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒ $\lambda_2=\frac{4L}{3}$ ⇒ $\lambda_3=\frac{4L}{5}$

⇒ $\lambda_2=\frac{4(120)}{3}$ ⇒ $\lambda_3=\frac{4(120)}{5}$

⇒ $\lambda_2=\frac{480}{3}$ ⇒ $\lambda_3=\frac{480}{5}$

⇒ $\lambda_2=160\ cm$ ⇒ $\lambda_3=96\ cm$

So the pipe is open at one end and closed at one end .

6 0

3 years ago

Match each exponential function to the description of its percent rate of change. 22% growth 12% decay 2% decay 20% growth 20% d

makvit [3.9K]

The exponential function is defined as y = a(1+r)^x, where "a" represents the original account and "r" the rate of growth or decay.

Then we have the following:

1) 22% grow

y = a( 1 + 22%/100 )^x = a(1.22)^x

So the solution is: 124(1.22)^x

2) 12% decay

y = a( 1 - 12%/100 )^x = a(0.88)^x

So the solution is: y = f(x) = 44(0.88)^x

3) 20% decay

y = a( 1 - 20%/100 )^x = a(0.8)^x

So the solution is: f(x) = 22(0.8)

4) 12% Groth

y = a( 1 + 12%/100 )^x = a(1.12)^x

So the solution is: f(x) = 42(1.12)^x

4 0

3 years ago

This is converting to polar form, I need help and the answer too.

Mila [183]

Answer:

2 cis (7/6 pi)

Step-by-step explanation:

r = sqrt( a^2 + b^2)

r = sqrt (-sqrt(3) )^2 + (-1)^2)

= sqrt(3 +1)

= sqrt(4)

= 2

theta = arctan (b/a)

theta = arctan (-1/-sqrt(3))

theta = 30

but this is in the third quardrant -a and -b

so add 180

theta = 210 degrees

convert this to radians

210 * pi/180 = 210/180 * pi = 21/18 * pi = 7/6 * pi

r cis (theta)

2 cis (7/6 pi)

7 0

2 years ago

Is this true? And also how does the equation from y-3=3(x-4) become a positive <br> y+3=3x-12?

EastWind [94]

Step-by-step explanation:

the right equation is :

y-y1=m(x-x1)

y+3=3(x+4)

y+3= 3x+12

y=3x+12-3

y=3x+9

7 0

2 years ago