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strojnjashka [21]
3 years ago
15

What are the integer solutions to the inequality below? 4x+1<5x≤3(x+2)

Mathematics
1 answer:
Sindrei [870]3 years ago
7 0

Answer:

1<x≤3

Step-by-step explanation:

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Given the following triangle side lengths, identify the triangle as acute, right or obtuse. Show your work.
Shkiper50 [21]
Let "a", "b" and "с"  be sides of the triangle ("с" is the longest side).
The triangle will be:

right if       a² + b² = c²
аcute if     a² + b² > c²    
obtuse if   a² + b² < c²    

a.
a=3, b=4 and c=5

a² + b² = 3² + 4² = 9 + 16 = 25   and   c² = 5² = 25

25 = 25   ⇒  right triangle.

b.
a=5, b=6 and c=7

a² + b² = 5² + 6² = 25 + 36 = 61   and   c² = 7² = 49

61 > 49   ⇒  аcute triangle.

c.
a=8, b=9 and c=12

a² + b² = 8² + 9² = 64 + 81 = 145   and   c² = 12² = 144

145 > 144   ⇒  аcute triangle.
4 0
3 years ago
What is the cross section that is perpendicular to the base of a cylinder
Dennis_Churaev [7]
Circle
a cross section cut parallel to the base would result in a shape similar to the base.
3 0
3 years ago
Find the area of the shaded region
SOVA2 [1]

We know that, Area of a Circle is given by : πR²

Where : R is the Radius of the Circle.

We can Notice that : The Given Figure is One - Fourth of the Circle with Radius 'R'

\mathsf{\implies Area\;of\;One\;Quarter\;of\;the\;Circle = \frac{\pi R^2}{4}}

We can Notice that : The Quarter of the Circle is divided into 3 Equal Parts and The Shaded Region is One of the Equal Part.

\mathsf{\implies Area\;of\;Shaded\;Region = \frac{\frac{\pi R^2}{4}}{3}}

\mathsf{\implies Area\;of\;Shaded\;Region = {\frac{\pi R^2}{12}}}

3 0
3 years ago
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The table gives points on a line. What is the equation of the line?
Sedbober [7]

Answer:

The answer would be y= -2x + 5

Step-by-step explanation:

If you look at your table you can see a pattern in the Y collum. It's being subtracted by two each time.

4 0
3 years ago
A, B, C, and D have the coordinates (-8, 1), (-2, 4), (-3, -1), and (-6, 5), respectively. Which sentence about the points is tr
DedPeter [7]
For this case we observe that the lines AB (red) and CD (purple) are cut at one point.
 We observe that the slopes of both lines are different (they are not reciprocal opposites).
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 Answer:
 
AB and CD are intersecting lines but are not perpendicular.
 
See attached image.

4 0
3 years ago
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