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strojnjashka [21]
3 years ago
15

What are the integer solutions to the inequality below? 4x+1<5x≤3(x+2)

Mathematics
1 answer:
Sindrei [870]3 years ago
7 0

Answer:

1<x≤3

Step-by-step explanation:

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Select two polynomials that have a sum of 16n^3+13n^2+7n-10 A. 8n^3 - 5n +11n^2 - 5 B. 7n^2 + 8n - n^3 + 2 C. 15n^2 - 10n + 3n^3
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Answer:

Step-by-step explanation:

We have the polynomial

16n^3+13n^2+7n-10   ( 1 )

To solve this problem we have to take into account that only we can sum term with the same order in the variable. We have the polynomials

8n_{3}-5n+11n^{2}-5\\7n^2 + 8n - n^3 + 2\\15n^2 - 10n + 3n^3 - 4\\2n^2 + 12n - 5 + 8n^3

we can note (by summing term by term) that only the sum of the first and the fourth equation correspond to the given polynomial ( 1 ) of the problem. If we organize these polynomials (that is, write the equation down in a form where higher order appears first ) we have

8n^3 +11n^2 - 5n  - 5\\ 8n^3+2n^2 + 12n - 5\\

and if we sum we obtain

16n^3+13n^2+7n-10

that is what we was looking for

I hope this is useful for you

regards

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