Answer:
The first answer.
Step-by-step explanation:
Manuel doubles the size of the poster, so the area is doubled!
The limit values of the indicated value, 2 pounds, are the boundaries.
The boundaries of 2 pounds are;
<h3>Method used to find the boundaries of the indicated value</h3>
The boundaries of an indicated value are the upper and lower bounds of
the value, which are the possible minimum or maximum values the
number may be before being rounded to the current value.
The indicated value = 2 pounds
The lowest possible value, 2 pounds can be before rounding up is 1.5 pounds.
Therefore;
- 1.5 pounds is the lower bound of 2 pounds.
The highest possible value of 2 pounds is 2.44999... pounds which is approximately 2.5 pounds
Therefore;
- The upper bound of 2 pounds is 2.5 pounds
Which gives;
The boundaries of 2 pounds are;
Learn more about upper and lower bounds here:
brainly.com/question/17644296
7 because a(one side)= 1/sqrt2 * hypotenuse (7*sqrt2) THis equals 7
