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BabaBlast [244]
2 years ago
5

I need help on this can some one explain it and answer please!!!!

Mathematics
1 answer:
Alex_Xolod [135]2 years ago
6 0

Answer:

4(a). C= 3 + 1.5x

b. 'x' stands for the number of times the cup is refilled.

c. 3 + 1.5 (5)= $10.50

d. My answer to part (c) makes sense because the price of the cup is $3, and I have to pay $1.50 for each additional refill, in accordance to the formula I wrote.

Step-by-step explanation:

The original price of the cup is 3 dollars, but with each refill you get, you have to pay $1.50.

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Find the derivative of the inverse function of the original function f(x)=(x+1)^3-5
____ [38]

Answer:

Step-by-step explanation:

let f(x)=y

y=(x+1)^{3} -5\\flip ~x~and~y\\x=(y+1)^{3}-5\\(y+1)^{3}=x+5\\y=(x+5)^{\frac{1}{3} } -1\\or~f^{-1}(x)=(x+5)^{\frac{1}{3} } -1\\(f^{-1})'(x)=\frac{1}{3} (x+5)^{\frac{-2}{3} }

4 0
3 years ago
Not sure how to go at this at all, please help.
ss7ja [257]
Here ya go answer down below

8 0
2 years ago
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Multiply write in simplest form 20 × 3/4
dalvyx [7]
Multiply straight across and then just simply your answer. I divided by 2.

5 0
3 years ago
matthew lives 6 miles east of the school drew lives 8 miles north of the school. what is the shortest distance between the two h
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Answer:

Step-by-step explanation:

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7 0
3 years ago
Find the probability that the mean annual preciptiation will be between 32 and 34 inches. variable is normally distributed
liq [111]
Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.

This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.  
                                                                     34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
                                                                           1.9
                                                                      32 in - 31.2 in
and that to the left of 32 in   is               z = ---------------------- = 0.421
                                                                             1.9

Know how to use a table of z-scores to find these two areas?  If not, let me know and I'll go over that with you.


My TI-83 calculator provided the following result:

normalcdf(32, 34, 31.2, 1.9) = 0.267  (answer to this sample problem)

5 0
3 years ago
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