Which will melt faster: ice made from tap water, distilled water, or salt water?

Chemistry

1 answer:

Karo-lina-s [1.5K]3 years ago

7 0

The answer is ice made from tap water

You might be interested in

What is the electron configuration of the neutral lithium atom?

mote1985 [20]

<span>the electron configuration of the neutral Atom
1s2 2s1
should be your answer have a good day </span>

8 0

4 years ago

Which is the Net Ionic Equation for:

arlik [135]

Answer: $2Fe^{3+}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+2Fe(s)$

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and are present in an aqueous state and represented in the form of ions.

Net ionic equation : In the net ionic equations, we do not not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The complete balanced ionic equation will be:

$2Fe^{3+}(aq)+6Cl^-(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+6Cl^-(aq)+2Fe(s)$

In this equation, $Cl^-$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be:

$2Fe^{3+}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+2Fe(s)$

3 0

3 years ago

Calculate the number of grams of COOH 3 CH in the vinegar.

IRINA_888 [86]

If you are given the number of moles of sodium bicarbonate, use the balanced chemical equation. The molar mass of the acetic acid is 60 grams per mole. Using stochiometric balance.

Number of moles of acetic acid = 3 moles NaHCO3 (1 mol CH3COOH/1 mol NaHCO3) = 3 moles of acetic acid

Grams of acetic acid = 3 moles of CH3COOH (60 g CH3COOH/1 mol CH3COOH) = <span>180 grams of acetic acid</span>

4 0

3 years ago

How many protons are in oxygen's nucleus?

UkoKoshka [18]

There are eight protons in an Oxygen's nucleus.

8 0

4 years ago

Read 2 more answers

Could someone explain this to me I gotta test tomorrow on this

serious [3.7K]