A student heats a sample of Copper (II) sulfate in a crucible and records the data shown in the table. What is the complete form
2 answers:
You might be interested in
Amines are derivatives of Ammonia (NH₃) in which atleast one hydrogen atom is replaced by an alkyl group. Amines are further classifies as;
Primary Amines:
In primary amines the nitrogen atom is attached to two hydrogen atoms and one alkyl group.
Secondary Amines:
In secondary amines the nitrogen atom is attached to two alkyl groups and one hydrogen atom.
Tertiary Amines:
In tertiary amines the nitrogen atom is attached to three alkyl groups, hence it has no hydrogen atom.
Below are three isomers of tertiary amines with molecular formula C₅H₁₃N.
Primary Amines:
In primary amines the nitrogen atom is attached to two hydrogen atoms and one alkyl group.
Secondary Amines:
In secondary amines the nitrogen atom is attached to two alkyl groups and one hydrogen atom.
Tertiary Amines:
In tertiary amines the nitrogen atom is attached to three alkyl groups, hence it has no hydrogen atom.
Below are three isomers of tertiary amines with molecular formula C₅H₁₃N.
Explanation:
The given data is as follows.
Pressure (P) = 760 torr = 1 atm
Volume (V) = = 0.720 L
Temperature (T) = = (25 + 273) K = 298 K
Using ideal gas equation, we will calculate the number of moles as follows.
PV = nRT
Total atoms present (n) =
=
= 0.0294 mol
Let us assume that there are x mol of Ar and y mol of Xe.
Hence, total number of moles will be as follows.
x + y = 0.0294
Also, 40x + 131y = 2.966
x = 0.0097 mol
y = (0.0294 - 0.0097)
= 0.0197 mol
Therefore, mole fraction will be calculated as follows.
Mol fraction of Xe =
=
= 0.67
Therefore, the mole fraction of Xe is 0.67.