The net ionic equation for the neutralization reaction involving equal molar amount amount of HNo3 and KoH is
H^+ + OH^- = H2O (l)
explanation
write the chemical equation
HNO3 (aq) + KOH(aq) = KNO3(aq) +H2O (l)
ionic eequation
H^+(aq) + NO3^- (aq) + K^+9aq) OH^-(aq) = K^+ (aq) + NO3^-(aq) + H2O(l)
cancel the spectator ions( ions which does not take place in equation ) for this case is NO3^- and No3^-
thus the net ionic is
H^+(aq) + OH^- (aq) = H2O(l)
To know which is a better solvent between the two, one should know what will be the solute. It really depends on what type of solute you have. If the solute is polar then water is the better solvent for that type of solute. However, when the solute is a nonpolar substance then carbon tetrachloride is the better solvent.
223.44 grams is the answer. Multiply 2.28 times the gram formula mass of h2so4
Answer: Andre. If it is used as an antifreeze, one would infer that it's freezing point is less than water.
Explanation:
The freezing point of ethylene glycol alone (100%) is -12.9oC. That is somewhat less than the freezing point of water but nowhere near the freezing point of water containing 70% ethylene glycol.
The answer would be: C. 160.3 J/mol*K
To solve this question, you need to know the equation for Gibbs free energy formula. Entropy is expressed as delta S. The temperature would be expressed as T. Don't forget that temperature use Kelvin as unit, not Celsius
The formula would be:
G= H- T*S
130.5 kJ/mol= 178.3kJ/mol - (25+273.15K)*S
(298.15K)*S=178.3kJ/mol - 130.5 kJ/mol
S= (47.8kJ/mol)/ 298.15K=
S= 0.1603 kJ/mol*K= 160.3 J/mol*K ------> 1kJ= 1000J
