Answer:
Thrust = 200 N
Explanation:
The engine thrust can be found by using the following formula:
where,
m = mass flow rate of the fuel = 0.05 kg/s
v = velocity of ejected gases = 4000 m/s
Therefore, using the given values in the equation, we get:
<u>Thrust = 200 N</u>
The force of friction acting on him is 122 N. The correct answer is option C
<h3>
What is Friction ?</h3>
Friction is a force that opposes the motion of a static or a moving object.
Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg
The given parameters are;
- Coefficient of kinetic friction μ = 0.15
- Frictional force = ?
The normal reaction N on the body = mg
N = 83 x 9.8
N = 813.4 N
The Frictional force formula is = μN
= 0.15 x 813.4
= 122.01 N
Therefore, the force of friction acting on him is 122 N approximately.
Learn more about Friction here: brainly.com/question/24338873
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Answer:
1200 Sm^2mol^-1
Explanation:
Given data :
conductivity of water ( kwater ) = 76 mS m^-1 = 0.076 Sm^-1
conductivity of kcl (aq)( Kkcl ) = 1.1639 Sm^-1
Kkcl = 1.1639 - 0.076 = 1.0879 Sm^-1
Resistance = 33.21 Ω
where conductivity can be expressed as =
hence cell constant = conductivity * Resistance
= 1.0879 * 33.21 = 36.13m^-1
conductivity of CH3COOH ( kCH3COOH ) = 36.13 / 300
= 0.120 Sm^-1
<u>Determine the molar conductivity of acetic acid</u>
= ( kCH3COOH * 1000 ) / C
C = 0.1 mol dm
= (0.120 * 1000) / 0.1 = 1200 Sm^2mol^-1
When an object does not move even on pushing , static frictional force acts on in opposite direction of the applied force to stop the object from moving. static frictional force is a self adjusting force and it adjust its value according to the applied force if the applied force is smaller than the maximum value of static frictional force. The object starts moving once the applied force on it becomes greater than the maximum static frictional force. hence the statement is true.