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3 years ago

Can someone help me on 2 science question,

2 answers:

5 0

1. The answer ur question is A.<span>observe the phase of the moon each night until a full moon can be seen.

2.The answer 2 ur secound question is </span><span>B.The Moons position relative to the sun and earth as it revolves around sun.</span>

Nataly_w [17]3 years ago

3 0

Answer:c

Explanation:

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I need help asap plzz

jekas [21]

Its c). cause they are separate variables

7 0

3 years ago

Read 2 more answers

A series AC circuit contains a resistor, an inductor of 220 mH, a capacitor of 5.50 μF, and a generator with ΔVmax = 240 V opera

ki77a [65]

Answer:

$Xl=wL=69.11503383 ohm$

$Xc=\frac{-1}{wC}= -578.7452476 ohm$

$Z=\frac{240}{140*10^-3}=1.714285714 kilo-ohm$

$R=2.223915928 kilo-ohm$

$\alpha = -12.90698798 centigrades$

Explanation:

$L=220*10^-3$

$C=5.50*10^-6$

$Vmax=240V$

$Imax=140*10^-3$

$w=2\pi f=2\pi *50=314.1592654$

The capacitive reactance is given by:

$Xc=\frac{-1}{wC}=-578.7452476 ohm$

Now, The inductive reactance is given by:

$Xl=wL=69.11503383 ohm$

By the ohm´s law, the electrical impedance is:

$V=IZ$

$Z=\frac{V}{I}$

$Z=\frac{240}{140*10^-3}=1.714285714 kilo-ohm$

The total impedance is:

$Z=R+jX\\\\$ (*)

Where X is the total reactance given by:

$X=Xl+Xc=69.11503383-578.7452476=-509.6302138$

Let´s calculate the real part of Z using (*):

$R=1714.285714+509.6302138$

$R=2.223915928 kilo-ohm$

Finally the angle between the current and the voltage is equal to the impedance angle:

$\alpha=arctan(\frac{-509.6302138}{2223.915928})$

$\alpha =-12.90698798 centigrades$

8 0

3 years ago

I need help with number 3,

just olya [345]

Simple the ozone layer is the layer in the atmosphere that protect us from the harmful rays the sun produces and without the ozone layer things will get catostrophic if you dont live in the ocean or a cave

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3 years ago

Mass m, moving at speed 2v, approaches mass 4m, moving at speed v. The two collide elastically head-on. Part A Find the subseque

meriva

Thank you for posting your question here at brainly. A mass of m moves with 2V towards in the opposite direction of a mass, 4m moving at a speed of V, the speed of m was 2/5V and the mass of 4m was 7.5V. I hope it helps.

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4 years ago

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How were the Crusades different from some of the wars we’re more familiar with today, such as the Vietnam War, the Iraq War, or

Colt1911 [192]

The Crusades were religious wars, the wars we're familiar with today are more based on morals, not religion.

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4 years ago