The amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is is 8 times the initial amount of heat.
<h3>What is heat?</h3>
The temperature increment will lead to the increase in the internal energy of the object. This internal energy is the heat.
Given is the change in temperature ΔT = 7-4 =3°C., diameter D to 2D,
Q = Cp x ρ(4π/3)D³ x 3..................(1)
and Q' = Cp x ρ(4π/3)(2D)³ x 3
Q' = Cp x ρ(4π/3)8D³x 3..................(2)
Dividing both the equation, we have
Q' / Q =8
Q' = 8Q
Thus, the amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is 8 times the initial amount of heat.
Learn more about heat.
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Answer:
Acceleration = 3m/s^2
Displacement = 126 m
Explanation:
The velocity changed from 12 to 30 m/s in 6 seconds. Using the formula for acceleration we get
(30-12)/6= 18/6= 3m/s^2
Displacement is d=.5a*t^2+v0*t
Inputting acceleration, time, and velocity leaves us with
d=1.5 * 36 + 12 * 6 = 54 + 72 = 126 m
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