All categories

3 years ago

At the beginning of the week, a puppy weighed 514 pounds. During the week, the puppy gains 8 ounces.

Mathematics

2 answers:

dangina [55]3 years ago

8 0

You can use socratic for that

Korvikt [17]3 years ago

8 0

♣ explanation ♣

---------------------------------------------------------------------------------------------------------------

Add 8 <em>ounces</em> onto 5 to get 13, and then, add the <u><em>unit fraction</em></u> 1/4 onto it and you get 13 1/4 as your <u><em>non-simplified</em></u> mixed number answer.

---------------------------------------------------------------------------------------------------------------

But wait! The answer must be simplified into the mixed number, "5 3/4" by <u><em>dividing</em></u> the current answer by 8 1/2, or any other number that <u><em>involves</em></u><em> </em><u><em>similarities</em></u> to the fractions' characteristics.

You might be interested in

What is the answer to 3 5/8 - 2 1/8 =

Allisa [31]

The answer would be 1 1/2 think of it as 3-2 and then 5/8 - 1/8

4 0

3 years ago

Read 2 more answers

A jar contains only pennies, nickels, dimes, and quarters. There are 25 pennies, 21 dimes, and 29 quarters. The rest of the

OlgaM077 [116]

<h3>Answer: </h3><h3>There are 75 coins that aren't nickels. </h3><h3>One equation you could use is 75+n = 92</h3>

(This solves to n = 17 meaning there are 17 nickels)

=====================================================

Explanation:

"There are 25 pennies, 21 dimes, and 29 quarters", so there are 25+21+29 = 75 coins so far. This is the amount of coins that aren't nickels. The rest are nickels, which is some amount n. This adds to the 75 to get 75+n. Set this equal to 92 because there are 92 coins in all. That's how we end up with 75+n = 92.

-----

Extra info

The equation 75+n = 92 is the same as n+75 = 92. Subtract 75 from both sides to isolate n. You should get n = 17 after doing so.

3 0

4 years ago

Use the rational zero theorem to determine all possible rational zeros of f(x)=3x^3-2x^2+5x+9

sukhopar [10]

Answer:

work it out it is so easy

Step-by-step explanation:

8 0

3 years ago

What is the sum or difference?

dlinn [17]

1. Ans: Option (B) $-6x^4$

Explanation:
Given: $2x^4 - 8x^4$
Take the common out:
=> $x^4(2 - 8)$

Hence: => $[tex]-6x^4$ [/tex] (Option B)

2. Ans: Option (D) $-3y^5$

Explanation:
Given: $6y^5 - 9y^5$
Take the common term(s) out:
=> $y^5(6-9)$

Hence: => $-3y^5$ (Option D)

3. Ans: Option (B) $9x^2 - 12x + 6$ <span> quadratic trinomial

Explanation:
</span>Given: $6 - 12x + 13x^2 - 4x^2$

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> $13x^2 - 4x^2 - 12x + 6$
=> $9x^2 - 12x + 6$ (Option B)

4. Ans: Option (C) $7.3x^2 + 0.8x + 1.3$

Explanation:
In order to find the total number of C<span>ommon and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

</span>Common guppies: $3.1x^2 +6.0x + 0.3$ <span>
Endler's guppies: </span> $4.2x^2 - 5.2x + 1.0$
(add both)
-----------------------------------------------------------------
Total number: $7.3x^2 +0.8x + 1.3$
-----------------------------------------------------------------
Hence the ans is Option(C) $7.3x^2 + 0.8x + 1.3$

5. Ans: Option (D) $2x^2(133 - 18 \pi )$

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = $266x^2$

Now the area of the circular fountain:
Area of the Circular Fountain = $\pi r^2$
Since, r=6x
Therefore,
Area of the Circular Fountain = $\pi (6x)^2 = 36 \pi x^2$

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = $266x^2$ - $36 \pi x^2$
=> Final area of the Yard = $2x^2(133 - 18 \pi)$ (Option D)

6. Ans: Option (A) $56x^2$

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = $60x^2$

Now the area of the stadium:
Area of the stadium = 1x * 4x = $4x^2$

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= $60x^2$ - $4x^2$
=> Final area of the lot = $56x^2$ (Option A)

-i

4 0

3 years ago

Read 2 more answers

I need a models or visuals for that problem

Leya [2.2K]

Answer:I will be a mode

Step-by-step explanation:

4 0

3 years ago