The fact that this triangle is a right angle triangle makes you now have 2 angles and the 1 side given, so it should be solvable.
First, You know that A=46 and C=90 as it is the right angle, and you know that the sum of any triangle's angles is 180. so now B=180-(90-46)=44
Now to the sides,
sin(B)=opp./hyp.=b/c=8/c=sin(44)
so, c=8/sin(44) which is approximately 11.52 unit length
now, use Pythagoras to find a,
a=√c²-b² =√11.52²-8² which is approximately 8.3 unit length.
Hope this helps.
Answer:
a= 1 , b = 1/16 , c = 1/256 , d= 3/2 , e=4/9 , f= 16/81
Step-by-step explanation:
The first table is given as;
x 4⁻ˣ
-1 4
0 1
2 1/16
4 1/256
a= 1 , b = 1/16 , c = 1/256
The second table is given as;
x {2/3}^x
-1 3/2
0 1
2 4/9
4 16/81
d= 3/2 , e=4/9 , f= 16/81
Please, for clarity, use " ^ " to denote exponentiation:
Correct format: x^4*y*(4) = y*x^2*(13)
This is an educated guess regarding what you meant to share. Please err on the side of using more parentheses ( ) to show which math operations are to be done first.
Your (x+y)2, better written as (x+y)^2, equals x^2 + 2xy + y^2, when expanded.
The question here is whether you can find this x^2 + 2xy + y^2 in your
"X4y(4) = yx2(13)"
Please lend a hand here. If at all possible obtain an image of the original version of this problem and share it. That's the only way to ensure that your helpers won't have to guess what the problem actually looks like.
If you're looking for x then it's 7. The value of -4 is -4.
