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KatRina [158]
3 years ago
7

What is the value of xA. 76B. 56C. 46D. 66

Chemistry
1 answer:
vladimir1956 [14]3 years ago
7 0
It’s d I’m pretty sure
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How and why do ionic bonds form? Check all of the boxes that apply. Ionic bonds form between metal atoms and other metal atoms.
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2 Ionic bonds form between metal atoms and nonmetal atoms.

4 The less electronegative atoms transfers one or more electrons to the more electronegative atom.

5 The metal atom forms a cation and the nonmetal atom forms an anion.

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Is 4Na2CO3 a mixture why or why not?
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At 293 K, methanol has a vapor pressure of 97.7 Torr and ethanol has a vapor pressure of 44.6 Torr. What would be the vapor pres
Bad White [126]

Answer: The vapor pressure of a mixture of 80 g of ethanol and 97 g of methanol at 293 K is 78.3 torr.

Explanation:

According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.

p_1=x_1p_1^0 and p_2=x_2P_2^0

where, x = mole fraction in solution  

p^0 = pressure in the pure state

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_1+p_2p_{total}=x_Ap_A^0+x_BP_B^0

moles of ethanol=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{80g}{46g/mol}=1.7moles

moles of methanol= \frac{\text{Given mass}}{\text {Molar mass}}=\frac{97g}{32g/mol}=3.0moles

Total moles = moles of ethanol + moles of methanol = 1.7 +3.0 = 4.7

x_{ethanol}=\frac{1.7}{4.7}=0.36,

x_{methanol}=1-x_{ethanol}=1-0.36=0.64

p_{ethanol}^0=44.6torr

p_{methanol}^0=97.7torr

p_{total}=0.36\times 44.6+0.64\times 97.7=78.3torr

Thus the vapor pressure of a mixture of 80 g of ethanol and 97 g of methanol at 293 K is 78.3 torr.

8 0
4 years ago
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