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Artist 52 [7]
3 years ago
14

the difference between these two measurements: 60 m and 60.00 m How many sig figs does each contain? Clearly explain which digit

s are significant and which are not. Which measurement is more accurate? Which has more uncertainty? Are they the same measurement? How are they different?
Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

This problem is providing two measurements, 60 m and 60.00 m and asks for the difference in the significant digits, accuracy, uncertainty, whether they are the same or not and how they differ.

<h3>Significant figures:</h3>

In chemistry, the use of significant figures is crucial, because they define the most appropriate way to report a measurement. Thus, we can say that the more decimals a measurement has, the more accurate and the less uncertain it is. Also, if no decimal places are present, tracking zeros are not significant.

In such a way, one can conclude that 60 m has just one significant figure (0 does not count) whereas 60.00 m has four  (there is a decimal making all zeros significant), 60.00 m is more accurate as more decimal places are reported. On the other hand 60 m is the more uncertain as less decimals contribute to its accuracy.

In addition, we say they can be the same measurement, as long as they represent the same idea, sixty meters, the thing is 60.00 m is more accurate yet they refer to the same measurement.

Learn more about significant figures: brainly.com/question/11904364

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<u>Answer:</u> No, the reverse reaction must proceed to establish equilibrium.

<u>Explanation:</u>

K_p is the constant of a certain reaction at equilibrium while Q_p is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

The expression of Q_p for above equation follows:

Q_p=\frac{(p_{HI})^2}{p_{H_2}\times p_{I_2}}

We are given:

p_{HI}=1.055atm\\p_{H_2}=0.127atm\\p_{I_2}=0.134atm

Putting values in above equation, we get:

Q_p=\frac{(1.055)^2}{0.127\times 0.134}=65.41

We are given:

K_p=55.2

There are 3 conditions:

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As, Q_p>K_p, the reaction will be favoring reactant side or the reaction must proceed in the reverse direction.

Hence, no, the reverse reaction must proceed to establish equilibrium.

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