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algol [13]
3 years ago
6

Any absurd answers will be reported, no links either. Ill give branliest to someone with the best answer and someone who answere

d them all correctly

Physics
1 answer:
Alexandra [31]3 years ago
3 0

Answer:

1. D

2.C

3. A

4. B

5. D

I tried my best hopefuly you get good grade :)

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An electron and a proton are each accelerated from rest through a potential difference of 100 V. Afterward, which particle has t
Lena [83]

Explanation:

The De-Broglie wavelength in terms of potential difference is given by:

\lambda=\dfrac{h}{\sqrt{2meV} }

Where,

h is Planck's constant

m is mass of charged particle

V is potential difference

e is the amount of charge

It means that the De-Broglie wavelength is inversely proportional to the mass.

Since, the mass of the proton is more than the mass of the electron. So, the De- Broglie wavelength of the electron is larger than proton.

3 0
3 years ago
The energy of an onject as it is in motion is defined as?
Ivan

The energy of an object as it is in motion is defined as Kinetic energy.

<u>Explanation:</u>

The energy that is attained by an object when it is moving is called as Kinetic energy. It is the amount of energy that is essential for inducing an acceleration in an object and making it to displace from its idle position to the destination. When an object attains the acceleration it can have this kinetic energy until there is a change in the speed of the object with which it moves.

The forms of energy changes and it can take any form like thermal, electrical, electromagnetic,etc. Potential and kinetic energy are the two things under which these forms are energy are grouped. There can be a transferring of Kinetic energy from one object to another. The kinetic energy can also take any form of energy.  

7 0
3 years ago
Someone please help me
professor190 [17]
The answer is A. conduction
7 0
3 years ago
A satellite is to be launched into an orbit of radius,r Show that v = 2gr, where V is the
Snezhnost [94]

Explanation:

We start by using the conservation law of energy:

\Delta{K} + \Delta{U} = 0

or

\dfrac{1}{2}mv^2 - G\dfrac{mM}{r} = 0

Simplifying the above equation, we get

v^2 = 2G\dfrac{M}{r}

We can rewrite this as

v^2 = 2\left(G\dfrac{M}{r^2}\right)r

Note that the expression inside the parenthesis is simply the acceleration due to gravity g so we can write

v^2 = 2gr

where v is the launch velocity.

6 0
3 years ago
¿Qué valor de voltaje se requiere para que pasen 35 mA a través de una resistencia de 15 kΩ? Si se aplica ese mismo voltaje a un
ehidna [41]

Answer:

perdón yo no hablo inglés

8 0
3 years ago
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