Answer: D. They are the coldest stars.
Explanation:
Answer:
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Terminal speed=136.7 m/s
the formula for the terminal speed is given by :
V= 
m= mass=75 kg
a= area=0.2 x 0.4=0.08 m²
ρ= density of air=1.23 kg/m³
C= drag constant =0.8
so V= 
v= 136.7 m/s
<span>The answer is 6 Joules. The kinetic energy (KE) of an object is the product of half of the mass (m) of the object and the square of its velocity (v²): KE = 1/2m*v². We know that m = 0.75 kg and that v = 4 m/s. Therefore, KE = 1/2 * 0.75 kg * (4 m/s)² = 1/2 * 0.75 kg * 16 m²/s² = 6 kg*m²/s² = 6 J.</span>
W= 18*10^-3m
N= 18*710 ( because you have 710 slits per mm ) = 12780
lambda = 506*10^-9
The first step is to workout d.
d = w/N
d =18*10^-3m/12780
d =1.41*10^-6m
The second step is to work out the maximum number of m.
Since sin (theta) = less than 1, then m*lambda/d = less then 1,
therefore m= less than d/lambda
( I know thats confusing but trust me )
so m is less than 1.41*10^-6m/506*10^-9
= 2.7
Therefore use m = 2
Lastly put it all into the formula
dsin (theta) = m*lambda so:
theta = sin^-1(m*lambda/d)
theta = sin^-1(2*506*10^-9/1.41*10^-6m)
theta = 45.95 degrees or 46 degrees
