Answer:
1/ Using the first letter of the name of the elements.
2/ If the name of two or more elements begins with the same letter,the second letter of their name is also taken with first letter.
3/ Symbols are made by using the letters of the name of elements in other languages also.
Answer: It will take for the concentration of A to decrease from 0.900 M to 0.210 M is 28.75 s
Explanation:
Zero order reaction : A reaction is said to be of zero order if the rate is independent of the concentration of the reactants, that means the rate is directly proportional to the zeroth power of the concentration of the reactants.
Expression for the zero order kinetics:
![[A]=-kt+[A]_o](https://tex.z-dn.net/?f=%5BA%5D%3D-kt%2B%5BA%5D_o)
where [A] = concentration left after time t = 0.210 M
= initial concentration = 0.900 M
k= rate constant =
t = time for reaction = ?


Thus it will take for the concentration of A to decrease from 0.900 M to 0.210 M is 28.75 s
Density is defined as mass per unit volume.

the mass of 1 mL of CO₂ is - 0.0019 g
3.5 L = 3500 mL
then the mass of 3500 mL of CO₂ is - 0.0019 g/mL x 3500 mL = 6.65 g
mass of 3.5 L of CO₂ is 6.65 g
Answer:
Boiling point: 63.3°C
Freezing point: -66.2°C.
Explanation:
The boiling point of a solution increases regard to boiling point of the pure solvent. In the same way, freezing point decreases regard to pure solvent. The equations are:
<em>Boiling point increasing:</em>
ΔT = kb*m*i
<em>Freezing point depression:</em>
ΔT = kf*m*i
ΔT are the °C that change boiling or freezing point.
m is molality of the solution (moles / kg)
And i is Van't Hoff factor (1 for I₂ in chloroform)
Molality of 50.3g of I₂ in 350g of chloroform is:
50.3g * (1mol / 253.8g) = 0.198 moles in 350g = 0.350kg:
0.198 moles / 0.350kg = 0.566m
Replacing:
<em>Boiling point:</em>
ΔT = kb*m*i
ΔT = 3.63°C/m*0.566m*1
ΔT = 2.1°C
As boiling point of pure substance is 61.2°C, boiling point of the solution is:
61.2°C + 2.1°C = 63.3°C
<em>Freezing point:</em>
ΔT = kf*m*i
ΔT = 4.70°C/m*0.566m*1
ΔT = 2.7°C
As freezing point is -63.5°C, the freezing point of the solution is:
-63.5°C - 2.7°C = -66.2°C
Hello!
Data:
P (pressure) = 1 atm
V (volume) = 18.5 L
T (temperature) = 300 K
n (number of mols) = ? (in mol)
R (Gas constant) = 0.082 (atm*L/mol*K)
Apply the data to the Clapeyron equation (ideal gas equation), see:






Note:
If the feedback is to be considered, the closest r
esponse is 0.751 mol Nacl
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I hope this helps. =)