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suter [353]
3 years ago
7

Jeepers! You scared the life out of me! change into declarative sentence​

Chemistry
1 answer:
Sedbober [7]3 years ago
7 0

You scared the life out of me!

You is the subject,

Scared is the predicate,

<u>!</u> this sign is the punctuation mark.

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What is boiling point
klasskru [66]

Answer:

The temperature at which the given substance starts to boil is called boiling point.

I HOPE IT HELPED U

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2 years ago
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Bakit mahalaga ang paghahanda ng pambansang badyet sa isang taon?​
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Answer:

no lo sé chico ve a morir en un agujero

Explanation:

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2 years ago
Can someone help please​
Serhud [2]

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8 0
3 years ago
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Writing the net ionic equation
vazorg [7]

First write the molecular equation with states:


(NH4)2S (aq) + 2AgNO3(aq) → Ag2S (s) + 2NH4NO3


Now write a full ionic equation by separating into ions all substances that dissociate: anything (s) (g) or (l) does not dissociate


2NH4 + (aq) + S 2-(aq) + 2Ag+ (aq) + 2NO3- (aq) → Ag2S(s) + 2NH4 + (aq) + 2NO3- (aq)


To write the NET IONIC equation, inspect the full ionic equation above and delete anything that appears on both sides of the → sign:


Net ionic equation:

S 2-(aq) + 2Ag + (aq) → Ag2S(s)

3 0
2 years ago
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A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr
sergey [27]

Answer:

184.62 ml

Explanation:

Let p_1, v_1, and T_1 be the initial and p_2, v_2, and T_2 be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

p_1=p_2 ...(i)

v_1 = 200 ml

T_1= 26 ^{\circ}C = 273+26 =299 K

T_2= 3 ^{\circ}C = 273+3 =276 K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)

For the final condition,

p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)

Equating equation (i), and (ii)

\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}

\frac{v_1}{T_1}=\frac{v_2}{T_2}  [from equation (i)]

v_2=\frac{T_2}{T_1} \times v_1

Putting all the given values, we have

v_2=\frac{276}{299} \times 200 = 184.62 \; ml

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

7 0
2 years ago
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