<u><em>The answer is definitely the sun</em></u> because a sun is a star. Other stars are to far, so thats why its soo tinny. Some stars are brighter than the sun... But your answer is definitely <u><em>SUN</em></u>...
No, molecules don’t ever stop moving
C The number and types of bonds within the molecule.
Explanation:
In a molecule, the number and types of bonds present determines the amount of available energy therein.
When bonds are broken or formed, energy is usually released.
- Elements combine with one another in order to attain stability in this state.
- Through this process, they form bonds by attraction.
- Where atoms exchange their valence electrons by losing or gaining it, electrovalent bonds form.
- In covalent molecules, electrons are usually shared between atoms.
- An attraction result from this type of interaction.
- The bond formed stores energy in the process.
- When bonds are broken, energy is usually released. The energy accrues when the bond was being formed.
- In molecules, we have covalent bond.
Learn more:
Bond brainly.com/question/7213980
Covalent bonds brainly.com/question/5258547
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The grams of ethane present in a sample containing 0.4271 mole is 12.84 g
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation
Mole = mass / molar mass
With the above formula, we can obtain the mass of ethane. Details below
<h3>How to determine the mass of ethane</h3>
The following data were obtained from the question:
- Mole of ethane = 0.4271 mole
- Molar mass of ethane = 30.067 g/mol
- Mass of ethane =?
The mass of ethane present in the sample can be obtained as follow:
Mole = mass / molar mass
Cross multiply
Mass = mole × molar mass
Mass of ethane = 0.4271 × 30.067
Mass of ethane = 12.84 g
Learn more about mole:
brainly.com/question/13314627
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Answer:
c. 298 K
Explanation:
Nernst equation is an equation used in electrochemistry that relates the reduction potential of a reaction with the standard potential, temperature and concentrations of the reactants in that are been reducted and oxidized. The formula is:
E = E° - RT / nF ln [Red] / [Ox]
<em>Where R is gas constant (8.314J/molK), T is absolute temperature (In Kelvin), n are moles of electrons and F is faraday constant (K/Volt*mol)</em>
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In electrochemistry, standard temperature is taken as 298K. That means by assuming standard temperature we can substitute T as:
<h3>c. 298 K</h3>
