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julsineya [31]
4 years ago
7

Which of these acids occurs naturally in the body and performs regularly functions?

Chemistry
1 answer:
stiv31 [10]4 years ago
3 0
I believe it would be Carbonic Acid
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A 25 Ω resistor has a voltage drop of 12 V across it. Calculate the current flowing through the resistor
Yanka [14]

Answer:

0.48

Explanation:

i =  \frac{v}{r}

because we are looking for I which is current we say

I = 12÷25 which is 0.48.

4 0
3 years ago
Two containers hold the same radioactive isotope. Container A contains 1000 atoms, and container B contains 500 atoms. which con
enyata [817]

Answer:

The rate of decay of atoms in container A is greater than the rate of decay of atoms in container B.

Explanation:

From the question,

Container A contains 1000 atoms

Container B contains 500 atoms

<u>The rate of decay of atoms in container A is greater than the rate of decay of atoms in container B.</u>

The reason for such is due to the difference in the concentration of the isotopes. Container A which contains higher number of atoms will have the more changes of the release of the neutron as the changes of the hitting and splitting increases as the density of the atoms increases.

<u>Thus, the atoms in the container A will therefore decay faster than the atoms in the container B. </u>

8 0
3 years ago
At which position in its orbit was the Moon located during the 2015 supermoon total lunar eclipse?
Novay_Z [31]
On September 27, 2015, a rare total lunar eclipse of a supermoon occurred. A supermoon occurs when the entire lighted half of the Moon faces Earth (full Moon phase) and the Moon is at its closest point to Earth in its orbit.
7 0
3 years ago
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In two or more complete sentences describe how atomic radius changes as you move down a group in the periodic table and why.
FrozenT [24]

in two of they got harder

8 0
3 years ago
What is the overall cell potential for this redox reaction? Cd + Hg22+ → Cd2+ + 2Hg Given: Cd2+ + 2e− → Cd(s) = –0.40 and Hg22+
Hoochie [10]

Answer:  1.19 V

Explanation:

Standard potential for an electrochemical cell is given by:

E^0{cell} = standard electrode potential =E^0{cathode}-E^0{anode}

The E^0 values have to be reduction potentials.  

Given:

E^o_{Cd^{2+}/Cd}=-0.40V

E^o_{Hg_2^{2+}/Hg}=0.79V

Cd+Hg_2^{2+}\rightarrow Cd^{2+}+2Hg

Cadmium is losing electrons , undergo oxidation and thus act as anode. mercury is gaining electrons, undergo reduction and thus acts as cathode.

E^0{cell} = standard electrode potential =E^0{cathode}-E^0{anode}=0.79-(-0.40)=1.19V

Thus the standard potential for an electrochemical cell with the cell reaction is 1.19 V.

4 0
3 years ago
Read 2 more answers
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