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vodomira [7]
3 years ago
10

If the area of a square is 81 square meters, how many meters long is each side

Chemistry
1 answer:
Anarel [89]3 years ago
8 0
Area is length times width, so you would want to undo that. Since this is a square and the sides are equal, you would find the square root of 81 which is 9. Each side of the square is 9 meters
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You have 500.0 ml of a buffer solution containing 0.30 m acetic acid (ch3cooh) and 0.20 m sodium acetate (ch3coona). what will t
Nataly [62]
First, we should get moles acetic acid = molarity * volume

                                                                =0.3 M * 0.5 L

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then, we should get moles acetate = molarity * volume

                                                           = 0.2 M * 0.5L

                                                           = 0.1 mol

then, we have to get moles of OH- which added:

moles OH- = molarity  * volume

                   = 1 M    * 0.02L

                  = 0.02 mol

when the reaction equation is:


                 CH3COOH  +  OH-  → CH3COO-   +  H2O


moles acetic acid after adding OH- = (0.15-0.02) 
                                             
                                                            =  0.13M                                       

moles acetate after adding OH- =  (0.1 + 0.02)

                                                      =   0.12 M

Total volume = 0.5 L + 0.02 L= 0.52 L

∴[acetic acid] = moles acetic acid after adding OH- / total volume

                        = 0.13mol / 0.52L

                       = 0.25 M

and [acetate ) = 0.12 mol / 0.52L
 
                        = 0.23 M

by using H-H equation we can get PH:

PH = Pka + ㏒[salt/acid]

when we have Ka = 1.8 x 10^-5

∴Pka = -㏒Ka 

        = -㏒ 1.8 x 10^-5

       = 4.7

So by substitution:

∴ PH = 4.7 + ㏒[acetate/acetic acid]

         = 4.7 + ㏒(0.23/0.25)

        = 4.66
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3 years ago
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I think that the answer is (D)... I hope this helped

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The following data are obtained for the decomposition of N2O5 at a certain temperature: 2N2O5(g) ↔ 4NO2(g) + O2(g) Time(s) 0 200
cricket20 [7]

Answer:

K = 0.0003 s⁻¹

Explanation:

The reaction is

2N₂O₅ = 4NO₂ + O₂

The equilibrium is

K[N_{2} O_{5} ]=-\frac{1}{2} \frac{d[N_{2} O_{5} ]}{dt} \\\int\limits^y_x {d[N_{2} O_{5} ]}{} \, =-2k\int\limits^t_0 {dt} \,\\ln[N_{2} O_{5} ]=-2kt+ln[N_{2} O_{5} ]

a plot is attached

From the plot, the slope is -0.0006

-2 * K = -0.0006

K = 0.0003 s⁻¹

Download xlsx
6 0
3 years ago
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