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Oliga [24]
3 years ago
5

analytical chemists can detect very small amounts of amoin acids , down to 3x10^-21 mol. how many molecules of an amino acid (mr

=200) would this be ?
Chemistry
1 answer:
sesenic [268]3 years ago
6 0
The number of particles in one mole is given be Avagadro's number <span>6.022×10^23

Multiply by number of moles.

3 ×10^-21 mol * 6.022 ×10^23 molecules/mol = </span><span>1,807 molecules
(rounded to nearest whole number)
 </span>
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If you have 3.0 moles of argon gas at STP, how much volume will the argon take up?
Anestetic [448]
If you have 3.0 moles of argon gas at STP u would take up 2.5 volume
3 0
3 years ago
What are the properties of an ionic bond?
Goryan [66]

Answer:

Ionic Compounds have high boiling and melting points as they're very strong and require a lot of energy to break. The electrostatic forces of attraction between oppositely charged ions lead to the formation of ions. Ionic compounds form crystals. These compounds are brittle and break into small pieces easily.

Explanation:

3 0
3 years ago
4.Calculate the volume of 40g of Helium (He) at rtp.
Oksana_A [137]

Answer:

2.24dm³

Explanation:

Given parameters:

Mass of He = 40g

Unknown:

Volume of Helium  = ?

Solution:

To solve this problem, we convert the given mass to number of moles.

   Number of moles  = \frac{mass}{molar mass}  

   molar mass of He  = 4g/mol

  Number of moles  = \frac{4}{40}   = 0.1mole

So;

                  1 mole of gas at rtp occupies a volume of 22.4dm³

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4 0
3 years ago
Consider the reaction:
murzikaleks [220]

<u>Answer:</u> The formation of given amount of oxygen gas results in the absorption of 713 kJ of heat.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of oxygen gas = 83 g

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

\text{Moles of oxygen gas}=\frac{83g}{32g/mol}=2.594mol

For the given chemical equation:

2Fe_2O_3\rightarrow 4Fe+3O_2;\Delta H^o_{rxn}=+824.2kJ

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

By Stoichiometry of the reaction:

When 3 moles of oxygen gas is formed, the amount of heat absorbed is 824.2 kJ

So, when 2.594 moles of oxygen gas is formed, the amount of heat absorbed will be = \frac{824.2kJ}{3mol}\times 2.59mol=713kJ

Hence, the formation of given amount of oxygen gas results in the absorption of 713 kJ of heat.

7 0
3 years ago
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vaieri [72.5K]

Answer:

Explanation:

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8 0
3 years ago
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