Electronegativity
The tendency of an atom to pull electrons towards itself is called electronegativity.
It is the tendency of an atom to attract bonding pair of electrons towards itself. These atoms which are more electronegative are able to bear a negative charge and be stable.
Unlike electropositive elements which tend to lose electrons , electronegative elements hold on tightly to the electrons.
The electronegativity is measured using the Pauling Scale where the most electronegative element of the periodic table, Fluorine , is given a value of 4 and the rest of the elements have values lower than 4 according to the trends followed by their groups and periods.
The least electronegative element of the periodic table , Cesium has a value of 0.7 on the Pauling Scale.
Electronegativity increases when we move from left to right in the periodic table and it decreases (in general) when we move down the group.
(To know more about Electronegativity: https://brainly.in/question/5742635 )
As we know,
Density of Benzene = 876 Kg/m³
And,
Density of Water = 997 Kg/m³
So,
Specific Gravity is calculated as,
Specific Gravity = Density of Benzene / Density of Water
Specific Gravity = 876 Kg/m³ / 997 Kg/m³
Specific Gravity = 0.878
Every object having specific gravity less than 1 will float on water and if value is greater than 1 then it will sink.
Benzene being non-polar in nature does not mix with water and due to less density it will float on the surface of water.
The ostrich runs 21 N then goes back by 25 S
The displacement is -4 S
21 - 25 = -4
Answer:
0.1313 g.
Explanation:
- It is known that at STP, 1.0 mole of ideal gas occupies 22.4 L.
- Suppose that hydrogen behaves ideally and at STP conditions.
<u><em>Using cross multiplication:</em></u>
1.0 mol of hydrogen occupies → 22.4 L.
??? mol of hydrogen occupies → 1.47 L.
∴ The no. of moles of hydrogen that occupies 1.47 L = (1.0 mol)(1.47 L)/(22.4 L) = 6.563 x 10⁻² mol.
- Now, we can get the no. of grams of hydrogen in 6.563 x 10⁻² mol:
<em>The no. of grams of hydrogen = no. of hydrogen moles x molar mass of hydrogen</em> = (6.563 x 10⁻² mol)(2.0 g/mol) = <em>0.1313 g.</em>
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