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Dmitry_Shevchenko [17]
3 years ago
5

Consider the diagram and angle measurements shown below.

Mathematics
1 answer:
seropon [69]3 years ago
3 0

Answer: C

Step-by-step explanation:

BECUASE I TOOK THE TEST

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How many grams are there in 3.3 x 10^23 atoms of boron?
iren [92.7K]

5.924 g

Step-by-step explanation:

The average weight of a boron atom is 10.811 atomic mass units (AMU). Therefore 3.3 x 10^23 atoms of boron will weight;

3.3 x 10^23 * 10.811 = 3.56763 x 10 ^ 24

One (1) gram = 6.022 x 1023 AMU. Therefore to convert AMU to grams;

3.56763 x 10 ^ 24 / 6.022 x 10^23

= 5.924 g

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3 years ago
a quarterback rushed for a gain of 9 yards in the first play of a football game. on the very next play, he was sacked and lost 9
Svetlanka [38]
9 yards total because the quarterback didnt gain any yards during the second play
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4 years ago
Someone help me plz it’s fast easy plz
Fantom [35]

Answer:

(2,3,4)

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4 years ago
Sally ran 2 1/4 miles in 1/2 hour. What is her speed in miles per hour?
weqwewe [10]
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I’m what quadrant does theta lie if the following statements are true? Sec(theta)<0 and (sec (theta) )(csc (theta) ) > 0
viktelen [127]

Because the cosine and sine must be negative when evaluated in theta, the angle lies on the third quadrant.

<h3>In which quadrant is the endpoint of the segment that defines the angle?</h3>

We know that if:

  • cos(θ) > 0, then we are on the first or fourth quadrant
  • sin(θ) > 0, then we are on first or second quadrant.

Here we know that:

sec(θ) < 0

And we know that:

sec(θ)  = 1/cos(θ)

Then we have cos(θ) < 0

We also have that:

sec(θ)*csc(θ) > 0

Because sec(θ) < 0, we must have that csc(θ) < 0.

Remember: csc(θ) = 1/sen(θ)

Then sen(θ) < 0.

Then we have the two conditions:

sen(θ) < 0

cos(θ) < 0

  • The cosine is negative on the third and second quadrants.
  • The sine is negative on the third and fourth quadrants.

The only quadrant where both are negative is the third quadrant, so that is the correct option.

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