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nirvana33 [79]
3 years ago
9

Identify the response variable and whether the setting involves a single sample, a matched pairs, or two independent samples.

Mathematics
1 answer:
Helga [31]3 years ago
6 0

Answer:

1. single sample design

2. matched pairs

3. two independent samples.

Step-by-step explanation:

the response variable is known as the dependent variable, it is the variable that the researcher is interested i finding. the response variable is the x variable that responds to changes in the independent variable.

1.

In this question the researcher has only one sample that is the specimen. that is the reference specimen that she obtained. Therefore it is a single sample design.

the response variable here is the measurement of concentration.

2. In this question we have two pairs, men and women. The researcher is interested in comparing attitudes as she interviews them. so response variable is attitude or behavior

3. this is a 2 independent sample design. The researcher is using two different methods to test and their average is being compared.

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What is the slope of a line perpendicular to the line whose equation is 2x+2y=28
malfutka [58]

Answer:

1

Step-by-step explanation:

1) First, place the given equation in slope-intercept form (y = mx +b format) to find its slope easier. Isolate the y:

2x + 2y = 28\\2y = -2x + 28\\y = -x+14

So, the equation of the line in slope-intercept form is y = -x + 14. When an equation is in slope-intercept form, the m, or the coefficient of the x-term, represents the slope. Thus, the slope for the given line would be -1.

2) Lines that are perpendicular have slopes that are opposite reciprocals of each other. We need to find the opposite reciprocal of -1, then.

To find the opposite reciprocal of a number, write the given number as a fraction first -- making -1 be written as   -\frac{1}{1} -- then switch the sign and flip the numerator and denominator. So, the opposite reciprocal of -1 is 1, and 1 is the slope of the perpendicular line.

3 0
2 years ago
If the Diameter is ten then what is the area of it
Pepsi [2]

Answer:

78.54

Step-by-step explanation:

Hope this helps!

7 0
2 years ago
In Exercises 23–36, solve the system using either Gaussian elimina- tion with back-substitution or Gauss-Jordan elimination. 23.
Luba_88 [7]

Answer:

23) x= 3, y = 4

24) Any (x,y) values where x = 1.5 - 2y

Step-by-step explanation:

For the first system(23), it goes like this

[1 2 | 7]

[2 1 | 8]

We need to do L2 = L2 - 2L1, so now it is

[1 2   | 7]

[0 -3 |-6]

So, now we have:

-3y = -6 *(-1)

3y = 6

y = 2

x + 2y = 7

x + 4 = 7

x = 3

Now for system 24, we have:

[-1 2 | 1.5]

[2 -4| 3]

We do L2 = L2 + 2L1, so we have:

[-1 2 | 1.5]

[0 0| 0]

So there are infinite solutions for this system. The solution for this system will be each (x,y) pair where x = 1.5 - 2y.

5 0
3 years ago
Mrs Hong had some milk. She used of it to bake some waffles and
Sergio [31]

<u><em>Answer:</em></u>

Mrs. Hong originally had 900 ml of milk

<u><em>Explanation:</em></u>

The complete question is in the attached image

Assume that the amount of milk Mrs. Hong originally had was x ml

<u>We are given that:</u>

1- She used \frac{1}{6} of it to bake the waffles, <u>therefore</u>:

   Amount used in baking waffles = \frac{1}{6}x ml

2- She used 300 ml to bake a pie

3- Amount left is half the original amount, <u>therefore</u>:

   Amount left = \frac{1}{2}x ml

<u>We know that:</u>

Total amount = amount used in waffles + amount used in pie + amount left

<u>Substitute with the givens and solve for x:</u>

Total amount = amount used in waffles + amount used in pie + amount left

x = \frac{1}{6}x + 300 + \frac{1}{2}x\\  \\x-\frac{1}{6}x-\frac{1}{2}x = 300\\   \\\frac{1}{3}x = 300\\  \\x = 300*3 = 900 ml

<u>This means that:</u>

She originally had 900 ml of milk

Hope this helps :)

7 0
3 years ago
Can u do this plz urgent ​
maks197457 [2]

Answer:

1-1) A=6×5=30m² | P=6×2+5×2=12+10=22m

1-2) A=5×20=100mi² | P=5×2+20×2=10+40=50mi

2-1) A=16×6=96m² | P=16×2+6×2=32+12=44m

2-2) A=20×9=180km² | P=20×2+9×2=40+18=58km

3-1) A=14×17=238yd² | P=14×2+17×2=28+34=62yd

3-2) A=20×18=360mi² | 20×2+18×2=40+36=76mi

8 0
3 years ago
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