Answer:
From 0.75 to 1.25 hours
Explanation:
Given
See attachment for graph
Required
Point where they didn't move
This means that we identify the point where the distance didn't change.
Given that the distance is plotted on the y-axis, we simply check for the end points of any horizontal line on the graph
The horizontal line on the graph represents 30km and the time interval is: 0.75 to 1.25 hours.
<em>Hence, (c) is correct</em>
Answer:
a) Δx = t 0.05 + 0.5
, Δx = 0.5 cm, b) Do not present any problem
Explanation:
The kinematic equation for constant speed is
v = x / t
x = v t
a) the uncertainty can be calculated with
Δx = dx /dv Δv + dx /dt Δt
Δx = t Δv + v Δt
Speed is
v = (50.00 ± 0.05) cm / s
The most common uncertainty for the time of Δt = 0.01 s
We replace
Δx = t 0.05 + 50 0.01
Δx = t 0.05 + 0.5
We must know the time to have an explicit value, if we assume that the measure was t = 1s
Δx = 0.5 cm
b)
Do not present any problem since its value is not very small, we must take as soon as the quantum effects and the velocity are not so high that we must take into account the relativistic effects
The SI unit for frequency is Hertz (Hz), or simply, the reciprocal of a second. It measures how fast an object could be moving. In this case, the frequency would be 16 wave crests per 8 seconds (16/8 = 2). In simplified answer, the frequency is 2 per second, or 2 Hz.
I got false. But worthier answer is right.
