Answer:
We conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.
Step-by-step explanation:
We are given that Bottles of a popular cola drink are supposed to contain 300 ml of cola. The distribution of the contents is normal with standard deviation of 3 ml. 
A student who suspects that the bottler is under-filling measures the contents of six bottles. The results are: 299.4, 297.7, 301.0, 298.9, 300.2, 297.0
<u><em>Let </em></u> <u><em> = mean contents of cola bottles.</em></u>
<u><em> = mean contents of cola bottles.</em></u>
SO, Null Hypothesis,  :
 :  300 ml   {means that the mean contents of cola bottles is more than or equal to the advertised 300 ml}
  300 ml   {means that the mean contents of cola bottles is more than or equal to the advertised 300 ml}
Alternate Hypothesis,  :
 :  < 300 ml   {means that the mean contents of cola bottles is less than the advertised 300 ml}
 < 300 ml   {means that the mean contents of cola bottles is less than the advertised 300 ml}
The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about the population standard deviation;
                        T.S.  =  ~ N(0,1)
  ~ N(0,1)
where,  = sample mean contents of cola bottle =
 = sample mean contents of cola bottle =  = 299.03 ml
 = 299.03 ml
              = population standard deviation = 3 ml
 = population standard deviation = 3 ml
             n = sample of bottles = 6
So, <em><u>test statistics</u></em>  =   
     
                                =  -0.792
<em>Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is more than the critical value of z as -0.792 > -1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>
Therefore, we conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.