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kirill115 [55]
3 years ago
5

What is diffusion concentration gradient​

Mathematics
1 answer:
GenaCL600 [577]3 years ago
8 0
The concentration gradient represents the concept that, just as a ball rolls down a slope, during diffusion molecules move down the concentration gradient. Higher concentration gradients will result in higher rates of diffusion. As the molecules move the gradient evens out until equilibrium is reached. (don’t write this exact response, be sure to change it up)
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. William fills 1/3 of a water bottle in 1/6 of a minute. How much time will it
lesantik [10]

Answer:

1/2 minute

Step-by-step explanation:

We can use a ratio to solve

1/3 bottle     1 bottle

------------   = --------------

1/6 minute    x minutes

Using cross products

1/3x = 1/6 *1

1/3 x = 1/6

Multiply each side by 3

3 * 1/3x = 3 * 1/6

x = 3/6

x = 1/2

1/2 minute

3 0
3 years ago
Read 2 more answers
Which of the following relations is NOT a function?
Alexxandr [17]

Answer:

It is A.

Step-by-step explanation:

In function A we see that there are 2 ordered pairs with value 2 in the first position with y values 6 and 2. So this is not a function.

5 0
3 years ago
A company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution
salantis [7]

Answer:

No, there is no strong evidence that the percentage of the fleet out of compliance is different from their initial thought.

Step-by-step explanation:

We are given that a company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution control guidelines.

The company initially believed that 30% of the fleet was out of compliance.

<u><em>Let p = percentage of the fleet that was out of compliance.</em></u>

SO, Null Hypothesis, H_0 : p = 30%   {means that the percentage of the fleet out of compliance is same as their initial thought}

Alternate Hypothesis, H_A : p \neq 30%   {means that the percentage of the fleet out of compliance is different from their initial thought}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                 T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = percentage of the fleet out of compliance = \frac{4}{25} = 16%

           n = sample of systems tested = 25

So, <u><em>test statistics</em></u>  =  \frac{0.16-0.30}{{\sqrt{\frac{0.16(1-0.16)}{25} } } } }

                              =  -1.909

The value of the test statistics is -1.909.

<em>Since in the question we are not given with the level of significance at which hypothesis can be tested, so we assume it to be 5%. Now at 5% significance level, </em><u><em>the z table gives critical values between -1.96 and 1.96 for two-tailed test.</em></u><em> </em>

<em>Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that the percentage of the fleet out of compliance is same as their initial thought.

3 0
3 years ago
Angle DEF measures 75°. What is the measure of angle CFD? 105° 125° 150° 165°
marta [7]
The answer is 105 because 180-75=105
6 0
4 years ago
Eva is short on frosting! She works in a bakery and has 12 cakes to frost, but she is short 418 cups on the amount of frosting r
In-s [12.5K]

The frosting which will be short on each of Eva's 12 cakes shared equally on each will be \frac {11}{32}

Number of cakes to frost = 12

Shortage on required frosting = 4 \frac{1}{8}

<u>Spreading the frost on each of the 12 cakes available</u> :

Divide the shortage on required frost by the number of cakes

Shortage on required frosting ÷ Number of cakes to frost

\frac{33}{8} \div 12 = \frac{33}{8} \times \frac{1}{12} = \frac{(33\times1)}{96} = \frac {11}{32}

Therefore, each frosted cake will be short of \frac{11}{32} \: cups

Learn more :brainly.com/question/18109354

5 0
2 years ago
Read 2 more answers
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