Given:
Consider the equation is:

To prove:
by using the properties of logarithms.
Solution:
We have,

Taking left hand side (LHS), we get

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

![[\because \log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20x%5En%3Dn%5Clog%20x%5D)

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

Hence proved.
<span>x 2 + 2x + 1 if you wanted is just 4x+1
</span>
Answer:
Option B
Option E
Step-by-step explanation:
By the use of following postulates we can prove the two right triangles to be congruent.
1). HA - [Equal hypotenuse and an cute angles]
2). LL - [Two legs should be equal]
3). LA - [One leg and one angle must be equal]
4). ASA - [Two angles and the side containing these angles should be equal]
In the given right triangles,
1). OJ ≅ IL
2). ∠O ≅ ∠I
3). ∠J ≅ ∠L
Therefore, two postulates HA, ASA will be applicable for the congruence of the two triangles given.
Options A and E will be the answer.
It would be neither because 5 to be patrol would be -5 and to be perp it would be -1/5 there’s is no way to get 9 to 5
Answer:
I'm not sure what your asking