The air pushes the engine with an equal force in the opposite direction.
Whenever force is used there is an opposite yet equal affect.
Substances evaporate at different rates
Given :
A jogger runs 5.0 km on a straight trail at an angle of 60° south of west.
To Find :
The southern component of the run rounded to the nearest tenth of a kilometre.
Solution :
We know, southern component is given by :
Here, negative sign indicates south direction.
Therefore, the southern component of the run rounded to the nearest tenth of a kilometre is 4.3 km.
Hence, this is the required solution.
Answer:
Explanation:
First of all, well calculate the spring constant k
K = 2Ei/x^2
Where Ei = initial work required
x = initial stretch length
k = 2×7/0.017^2 = 48443J/m^2
Now work done in stretching it to 5.3cm (1.7 + 3.6) or 0.053m
EF = kx^2/2
48443 × 0.053^2/2 = 68J
Work done in stretching additional 3.6cm is equal to
68J-7J = 61J
Answer:
a) 323.4J
b) 0J
c) -323.4J
Explanation:
a) W=Fd
F=ma
solve for acc. using kinematics
v^2=vo^2+2a(x)
8.41=2a(12)
4.205=a(12)
0.35=a
F=(77)(0.35)
F=26.95N
W=26.95*12...... W=323.4J
b) No acceleration, thus no force, thus no work!
c) W=Fd
F=ma
find acc. using kinematics: v^2=vo^2+2a(x)
0=(2.9^2)+2a(12)
0=8.41+2a(12)
-8.41=2a(12)
-4.205=a(12)
-0.35=a
F=(77)(-0.35)
F=-26.95N
W=(-26.95)(12)
W=-323.4J
Yes, work can be negative!
