Answer:
26.64 m
Explanation:
Given the following :
Acceleration at ocean surface = 0.0800 m/s²
Distance covered if initial speed = 0.700 m/s and accelerates to a speed of 2.18m/s
Using the equation :
v² = u² + 2as
Where ;
v = final velocity ; u = initial velocity ; a = acceleration ; s = distance covered
Therefore,
v² = u² + 2as
2.18² = 0.7² + (2 × 0.08 × s)
4.7524 = 0.49 + 0.16s
4.7524 - 0.49 = 0.16s
4.2624 = 0.16s
s = 4.2624 / 0.16
s = 26.64 m
Answer:
14,300 lines per cm
Explanation:
Answer:
14,300 cm per line
Explanation:
λ400 nm to 400nm
We can find the maximum number of lines per centimeter, which is reciprocal of the least distance separating two adjacent slits, using the following equation.
mλ = dsin (θ)
In this equation,
m is the order of diffraction.
λ is the wavelength of the incident light.
d is the distance separating the centers of the two slits.
θ is the angle at which the mth order would diffract.
To find the least separation that allows the observation of one complete order of spectrum of the visible region, we use the maximum wavelength of the visible region is 700 nm.
d = mλ / sin (θ)
As we want the distance d to be the smallest then sin (θ) must be the greatest, and the greatest value of the sin (θ) is 1. For that we also use the longest wavelength because using the smallest wavelength, the longest wavelength would not be diffracted.
d = mλ / sin (θ)
d = 1 x 700nm / 1
= 700 nm
So, the least separation that would allow for the possibility of observing complete first order of the visible region spectra is 700 nm, and knowing the least separation we can find the maximum number of lines per cm, which is the reciprocal of the number of lines per cm.
n = 1/d
= 1 / 700 x 
= 1, 430,000 lines per m
= 14,300 lines per cm
<u>The maximum number of lines per cm, that would allow for the observation of the complete first order visible spectra.</u>
Answer:
a) its frequency
Explanation:
The color of visible light depends only on its frequency, not on the amplitude. In fact, the visible light spectrum can be classified into different colors according to the different frequencies:
Violet: 680-790 THz
Blue: 620-680 THz
Cyan: 600-620 THz
Green: 530-600 THz
Yellow: 510-530 THz
Orange: 480-510 THz
Red: 405-480 THz
And the color of the light has nothing to do with the amplitude of the wave. Therefore, the correct answer is
a) its frequency
Answer:
a) 3000 Hz;
b) 30 dB;
c) 1000 times.
Explanation:
a) From the human audiogram given on the figure below the black line represents the threshold for hearing the sound at each frequency. We see that the least intensity is necessary for the frequency of about 3000 Hz.
b) Using the same audiogram we see that we would need the sound of the intensity of about 30dB.
c) The least perceptible sound at 1000 Hz must be 0dB while at 100 Hz it is 30dB. These are logarithmic quantities. To transform them to the linear quantities we use the formula

where
is the hearing threshold at 1000 Hz.
Therefore we have the following

is the threshold at 1000Hz and
is the threshold at 100Hz.
By exponentiating we have

Now dividing these two equations we get

Therefore, the least perceptible sound at 100Hz is 1000 times more intense than the least perceptible sound at 1000Hz.
Note: I got these values unisng the audiogram that is attached here. The one that you have might be slightly different and might yield different answers.