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mrs_skeptik [129]
3 years ago
9

A woman climbs up a ladder in 1.37 s at 2.20 m/s. How tall is the ladder?

Physics
2 answers:
kaheart [24]3 years ago
7 0

Answer:

height = 3.014

Explanation:

to find the height, use the equation height = velocity * time

height = 2.2*1.37

height =3.014

ArbitrLikvidat [17]3 years ago
6 0

Answer:

The ladder is 3.014 m tall.

Explanation:

To solve this problem, we must use the following formula:

v = x/t

where v represents the woman’s velocity, x represents the distance she climbed (the height of the ladder), and t represents the time it took her to move this distance

If we plug in the values we are given for the problem, we get:

v = x/t

2.20 = x/1.37

To solve this equation for x (the height of the ladder), we must multiply both sides by 1.37. If we do this, we get:

x = (2.20 * 1.37)

x = 3.014 m

Therefore, the ladder is 3.014 m tall.

Hope this helps!

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Desde lo alto de un acantilado de 140 m, se lanza verticalmente un objeto hacia abajo con velocidad de 3m/s. Entonces la magnitu
grin007 [14]

Answer:

54

Explanation:

d = vo*t + ½*g*t²

d = 3*3 + ½*10*3²

d = 9 + 45

d = 54 m

entonces el objeto tiene 54 m de desplazamiento

7 0
3 years ago
At a certain place, Earth's magnetic field has magnitude B =0.703 gauss and is inclined downward at an angle of 75.4° to the hor
Irina18 [472]

Answer:

The charge flows in coulombs is

dq=1.843x10^{-5}C

Explanation:

The current magnitude of current is given by the resistance and the induced Emf as:

I=N*\frac{dF}{Rdt}

\frac{dq}{dt}=\frac{dF}{Rdt}=dq=N*\frac{dF}{R}

dq=\frac{N*\beta*A*(Cos(\alpha_f)-Cos(\alpha_i}{R}

N=1300, \beta=0.703, A=\pi*r^2=\pi*0.10^2=0.01\pi m^2, R=99.4+202=301.4Ω

\alpha_f=14.6,\alpha_i=165.4

Replacing :

dq=\frac{1300*0.703x10^{-4}*0.01\pi*(0.9667-(-0.9667))}{202+99.4}

dq=1.843x10^{-5}C

5 0
3 years ago
You are walking from your math class to your science class. You are carrying books
kolezko [41]

Answer:

1800J

Explanation:

Given parameters:

Weight of the book  = 20N

Total distance covered  = 45m + 15m + 30m  = 90m

Unknown:

Total work performed on the books  = ?

Solution:

To solve this problem we must understand that work done is the force applied to move a body through a certain distance.

So;

    Work done  = Force x distance

  Work done  = 20 x 90  = 1800J

8 0
3 years ago
A bike with 15cm diameter wheels accelerates uniformly from rest to a speed of 7.1m/s over a distance of 35.4m. Determine the an
Finger [1]

Answer:

9.47 rad/s^2

Explanation:

Diameter = 15 cm, radius, r = diameter / 2 = 7.5 cm = 0.075 m, u = 0, v = 7.1 m/s,

s = 35.4 m

let a be the linear acceleration.

Use III equation of motion.

v^2 = u^2 + 2 a s

7.1 x 7.1 = 0 + 2 x a x 35.4

a = 0.71 m/s^2

Now the relation between linear acceleration and angular acceleration is

a = r x α

where,  α is angular acceleration

α = 0.71 / 0.075 = 9.47 rad/s^2

8 0
3 years ago
Is it possible to be moving but not be in motion?
GREYUIT [131]

No. Motion is the thing that when you're moving, you're in it.

But it IS possible for one person to say you're moving and another person to say you're not moving, both at the same time, and both of them are correct !

4 0
3 years ago
Read 2 more answers
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