All categories

4 years ago

A woman climbs up a ladder in 1.37 s at 2.20 m/s. How tall is the ladder?

Physics

2 answers:

kaheart [24]4 years ago

7 0

Answer:

height = 3.014

Explanation:

to find the height, use the equation height = velocity * time

height = 2.2*1.37

height =3.014

ArbitrLikvidat [17]4 years ago

6 0

Answer:

The ladder is 3.014 m tall.

Explanation:

To solve this problem, we must use the following formula:

v = x/t

where v represents the woman’s velocity, x represents the distance she climbed (the height of the ladder), and t represents the time it took her to move this distance

If we plug in the values we are given for the problem, we get:

v = x/t

2.20 = x/1.37

To solve this equation for x (the height of the ladder), we must multiply both sides by 1.37. If we do this, we get:

x = (2.20 * 1.37)

x = 3.014 m

Therefore, the ladder is 3.014 m tall.

Hope this helps!

You might be interested in

Two horizontal rods are each held up by vertical strings tied to their ends. Rod 1 has length L and mass M; rod 2 has length 2L

antiseptic1488 [7]

Answer:

Rod 1 has greater initial angular acceleration; The initial angular acceleration for rod 1 is greater than for rod 2.

Explanation:

For the rod 1 the angular acceleration is

$\tau_1 = I_1\alpha _1 \\\\\alpha_1 = \dfrac{\tau_1}{I_1}$

Similarly, for rod 2

$\alpha_2 = \dfrac{\tau_2}{I_2}.$

Now, the moment of inertia for rod 1 is

$I_1 = \dfrac{1}{3}ML^2$ ,

and the torque acting on it is (about the center of mass)

$\tau_1 = Mg\dfrac{L}{2};$

therefore, the angular acceleration of rod 1 is

$\alpha_1 = \dfrac{Mg\dfrac{L}{2}}{\dfrac{1}{3}ML^2},$

$\boxed{\alpha_1 = \dfrac{3g}{2L} }$

Now, for rod 2 the moment of inertia is

$I_2 = \dfrac{1}{3}(2M)(2L)^2$

$I_2 = \dfrac{8}{3} ML^2,$

and the torque acting is (about the center of mass)

$\tau _2 = (2M)g \dfrac{(2L)}{2}$

$\tau _2 = 2MgL;$

therefore, the angular acceleration $\alpha_2$ is

$\alpha_2 = \dfrac{2MgL;}{\dfrac{8}{3} ML^2,}.$

$\boxed{\alpha_2 = \dfrac{3g}{4L}}$

We see here that

$\dfrac{3g}{2L} > \dfrac{3g}{4L}$

therefore

$\boxed{\alpha_1 > \alpha_2.}$

In other words , the initial angular acceleration for rod 1 is greater than for rod 2.

7 0

3 years ago

If you are in a spaceship that is sitting on the surface of a planet, you feel your weight. How does this compare to the weight

nordsb [41]

Answer:

You will feel more weight if it is accelerating out of the planet.

You will feel less weight if it is accelerating towards the planet.

Explanation:

The weight that you are observing or feeling is basically due to the change in acceleration of your fall or rising up in the spaceship. When the acceleration is stationary on the surface, you experience your normal weight due to the gravitational acceleration of that planet.

When the spaceship accelerates above or out of the planet you experience acceleration more than the acceleration of gravity hence more weight.

When the spaceship accelerates towards the planet you experience acceleration less than the acceleration of gravity hence less weight.

If the spaceship is free falling at the gravitational acceleration you experience a zero weight

8 0

4 years ago

The scientist most often credited with the idea that matter can have wave-like properties is:

Flura [38]

I believe the correct answer from the choices listed above is option B. The scientist most often credited with the idea that matter can have wave-like properties is de Broglie. He <span>related E=mc^2, E=hf and p=mv in order to acquire the de Broglie wavelength, whose formula λ=h/p where h is Planck's constant and p is momentum of the particle.</span>

6 0

4 years ago

Read 2 more answers

What is the momentum of a baseball with a mass of 4 kg being thrown at a velocity of 84 m/s towards the hitter

Delvig [45]

Answer:

<h3>The answer is 336 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 4 kg

velocity = 84 m/s

We have

momentum = 4 × 84

We have the final answer as

Hope this helps you

7 0

3 years ago

Read 2 more answers

Pulling a rubber band back and then letting it fly across the room is an example of

Cloud [144]

Answer:

Explanation:

because a elastic band uses elastic energy

7 0

3 years ago