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kow [346]
3 years ago
7

Balance the following equations:C(s) +CO2(g)- CO(g)

Chemistry
1 answer:
BabaBlast [244]3 years ago
8 0

Answer:

C(s)+CO₂(g)→2CO(g)

Explanation:

Basically you’re adding the compounds until they’re equal on both sides

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How much heat is required to decompose 25.5 grams of NaHCO3? 2NaHCO3(s) + 129 kJ 2Na2CO3(s) + H2O(
Vaselesa [24]
To determine the heat required in order to decompose a certain amount of a substance, we need information on the heat needed to decompose one mole of the substance. This value are readily available online and other sources. For this reaction, the heat needed is 129 kJ per 2 mol of NaHCO3. We calculate as follows:

129 KJ / 2 mol NaHCO3 (1 mol / 84.01 g ) (25.5 g NaHCO3 ) = 19.58 kJ of heat is needed.
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3 years ago
What do scientist use to measure the volume of a substance
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Scientists use a Graduated Cylinder
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3 years ago
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I need help
Liono4ka [1.6K]

Answer:

d and e - Sodium and antimony

Explanation:

The atomic numbers remain the same, while the mass numbers change (because neutrons are being added or taken away).

sodium has an atomic number of 19 and a mass number of 39 - in d, it has an atomic number of 19 but a mass number of 40. therefore, it is an isotope

antimony has an atomic number of 51 and a mass number of 121.60 - in e, it has an atomic number of 51, but a mass number of 123. therefore, it is an isotope

6 0
3 years ago
Complete this neutralization equation:<br> H2SO4 + Al(OH)3
elena-s [515]

Answer:

H2SO4 + Al(OH)3 = Al2(SO4)3 + H2O

Explanation:

4 0
3 years ago
Which pair shares the same empirical formula?
ZanzabumX [31]

Answer:- 3. CH_3 and C_2H_6

Explanations:- An empirical formula is the simplest whole number ratio of atoms of each element present in the molecule/compound.

For example, the molecular formula of benzene is C_6H_6 . The ratio of C to H in it is 6:6 that could be simplified to 1:1. So, an empirical formula of benzene is CH.

In the first pair, the ratio of C to H in first molecule is 2:4 that could be simplified to 1:2 and  the empirical formula is CH_2 . In second molecule the ratio of C to H is 6:6 and it could be simplified to 1:1. and the empirical formula is CH. Empirical formulas are different for both the molecules of first pair and so it is not the right choice.

In second pair, C to H ratio in first molecule is 1:2, so the empirical formula is CH_2 . The C to H ratio for second molecule is 1:4, so the empirical formula is CH_4 . Here also, the empirical formulas are not same and hence it is also not the right choice.

In third pair, C to H ratio in first molecule is 1:3, so the empirical formula is CH_3 . In second molecule the C to H ratio is 2:6 and it is simplified to 1:3. So, the empirical formula for this one is also CH_3 . Hence. this is the correct choice.

In fourth pair, first molecule empirical formula is CH. Second molecule has 2:4 that is 1:2 mole ratio of C to H and so its empirical formula is CH_2 . As the empirical formulas are different, it is not the right choice.

So, the only and only correct pair is the third one. 3. CH_3 and C_2H_6

4 0
3 years ago
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