The complete question is as follows: The equilibrium constant, Kp, for the following reaction is 10.5 at 350 K: 2CH2Cl2(g) CH4(g) + CCl4(g) Calculate the equilibrium partial pressures of all species when CH2Cl2(g) is introduced into an evacuated flask at a pressure of 0.968 atm at 350 K. PCH2Cl2 = atm PCH4 = atm PCCl4 = atm
Answer: The equilibrium partial pressures of all species, that is, 
, 
and 
is 0.420 atm, 0.420 atm and 0.128 atm.
Explanation:
For the given reaction equation, the initial and equilibrium concentration of involved species is as follows.
Initial: 0.968 atm 0 0
Equilibrium: (0.968 - 2x) x x
Now, 
for this reaction is as follows.
Thus, we can conclude that the equilibrium partial pressures of all species, that is, , and is 0.420 atm, 0.420 atm and 0.128 atm.
<span>Use the van't Hoff equation:
ln
(
K2
K1
)
=
Δ
HÂş
R
(
1
T1
â’
1
T2
)
ln
(
K2
7.6*10^-3
)
=
-14,200 J
8.314
(
1
298
â’
1
333
)
ln
(
K2
7.6*10^-3
)
=
â’
1708
(
0.00035
)
ln
(
K2
0.0076
)
=
â’
0.598
Apply log rule
a
=
log
b
b
a
-0.598 =
ln
(
e
â’
0.598
)
=
ln
(
1
e
0.598
)
Multiply both sides with e^0.598
K
2
e
0.598
= 0.0076
K
e
0.598
e
0.598
=
0.0076
e
0.598
K
2
=
0.0076
e
0.598
=
4.2
â‹…
10
â’
3
K2
=
4.2
â‹…
10
â’
3</span>
Because you can't make the pencil go back to normal form
Answer:
RNA
Explanation:
Central dogma is the process of the formation of protein from the sequence of nucleotide on DNA. It consists of two further processes Transcription and translation.
During Transcription, the information from the DNA sequence is transcripted in a sequence of RNA, that is single stranded and contains Uracil instead of Thymine. During Translation, the information from the RNA sequence is translated into a sequence of amino-acid, and a protein.
Hope it helps!
A)Cu2O(s) + C(s) ———> 2Cu(s)+ CO(g)
B)H2(g) +Cl2(g)———> 2HCl(g)
