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2 years ago

What is the concentration (molarity) of a solution created by dissolving 81.1 grams of Mg3P2 to create a 2.5 solution?

Chemistry

1 answer:

Vaselesa [24]2 years ago

8 0

Answer:

The concentration of Mg3P2 solution = 0.24mol/L

Explanation:

Mass = 81.1g

Volume = 2.5L

Concentration (C) of a solution = $\frac{Moles (n)}{Volume (V)}$

but moles = $\frac{mass}{Molar mass}$ and Molar mass of Mg3P2 = 134.88g/mol

Moles = $\frac{81.1g}{134.88g/mol}$

= 0.60mol

hence the concentration can be calculated by;

C = $\frac{0.60mol}{2.5L} \\$

= 0.24mol/L or 0.24M

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3 years ago

Consider the following unbalanced reaction: P4(s) + F2(g) → PF3(g) What mass of fluorine gas is needed to produce 120. g of PF3

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3 years ago

A student titrates a solution containing 0.050 moles of calcium hydroxide with phosphoric acid. How many moles of phosphoric aci

lina2011 [118]

Answer:

The answer to your question is 0.33 moles of H₃PO₄

Explanation:

Data

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Process

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3Ca(OH)₂ + 2H₃PO₄ ⇒ Ca₃(PO₄)₂ + 6H₂O

Reactants Elements Products

3 Ca 3

12 H 12

14 O 14

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6 0

3 years ago

What is the molarity of a solution made from dissolving 10.0 moles of NaOH into 5.0

Vladimir79 [104]

Answer:

Option D

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3 years ago