<u>Answer:</u>
Nitrogen gas be a mineral only, if it is in organic forms.
<u>Explanation:</u>
Most of the forms of organic nitrogen is not be taken by plants, with the exception in the form of small organic molecules. Also plants can promptly take the nitrogen when it is in other forms like ammonia and nitrate.
The microorganisms in the soil converts the organic forms of nitrogen to mineral form when they decompose organic matters and also fresh plant residues. This type of process is called mineralisation.
Answer:
8. the answer is B.
9. the answer is A.
Explanation:
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8. In this case, by bearing to mind that the limiting reactant is always completely consumed and the excess one remain as a leftover at the end of the reaction, we can also infer that as all the limiting reactant is consumed, it must determine the maximum amount of product as the excess reactant will hypothetically produce a greater mass than expected; thus, the answer to this question is B.
9. In this case, since the mole ratio of oxygen to water is 1:2, the following proportional factor is used to calculate the produced mass of water:
Thus, the answer is this case is A.
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Answer:
As electro-negativity decreases from Florine to downwards in the group and only Florine is above Chlorine, so Florine should react with sodium chloride solution to produce chlorine.
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Answer:
74
Explanation:
we know,
atomic number = number of protons
so,
atomic number = 74
Answer:
A solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.
Explanation:
The concentration of a solution in Molarity (M) stands for the number of moles of that substance contained in 1 L of solution.
Molarity = Concentration in mol/L = (Number of moles of solute) ÷ (Volume of solution in L)
Molarity = Concentration in mol/L = 0.105 M = 0.105 mol/L
Number of moles of solute = ?
Volume of solution in L = 1 L
0.105 = Number of moles of solute × 1
Number of moles of solute = 0.105 mole
Hence, a solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.
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