Nenenennenwnjwnnwnwnnw
1 answer:
You might be interested in
Step-by-step explanation:
Given the linear equation, y = ⅔x + 1, where the <u>slope</u>, m = ⅔, and the y-intercept, (0, 1) where<em> b</em> = 1.
<h3><u>Start at the y-intercept:</u></h3>In order to graph the given linear equation, start by plotting the coordinates of the y-intercept, (0, 1). As we know, the <u>y-intercept</u> is the point on the graph where it crosses the y-axis. It coordinates are (0, <em>b</em>), for which the value of b represents the value of the y-intercept in slope-intercept form, y = mx + b.
<h3><u>Plot other points using the slope:</u></h3>From the y-intercept, (0, 1), we must use the slope, m = ⅔ (<em>rise</em> 2, <em>run</em> 3) to plot the other points on the graph. Continue the process until you have sufficient amount of plotted points on the graph that you could connect a line with.
Attached is a screenshot of the graphed linear equestion, which demonstrates how I plotted the other points on the graph using the "rise/run" techniques" discussed in the previous section of this post.
