The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.
A plane that travels a distance
, in kilometers, with a bearing of
sexagesimal degrees can be represented in standard position by means of the following expression:
(1)
We can obtain the resulting vector (
) by the principle of superposition:
(2)
If we know that
,
,
,
,
and
, then the resulting vector is:

![\vec R = (5\sqrt{3}, 6) \,[km]](https://tex.z-dn.net/?f=%5Cvec%20R%20%3D%20%285%5Csqrt%7B3%7D%2C%206%29%20%5C%2C%5Bkm%5D)
The magnitude of the resultant is found by Pythagorean theorem:

And the bearing is determined by the following <em>inverse</em> trigonometric relationship:
(3)
If we know that
and
, then the magnitude and the bearing of the resultant is:




The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.
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Answer:
I think it is B. 30 degrees
Step-by-step explanation:
Because if ZUY is 90 degrees and half of 90 degrees is 45 degrees but TUZ is a little bit less than the middle part of ZUY it has to be less than 45 degrees by a little bit and the only option would be 30 degrees. Hope this helped (:
FOIL (first outside inside last)
x^2-5x+5x-25 = x^2-25
Answer:
-16.3 ≥ q
Step-by-step explanation:
–5.3 ≥ 6.7 + 4.3 + q
Combine like terms
–5.3 ≥ 11 + q
Subtract 11 from each side
–5.3-11 ≥ 11-11 + q
-16.3 ≥ q
Circumference of entire circle = 2 * PI * 10
circumference of entire circle =
<span>
<span>
<span>
62.832 feet
81 degrees is (9/40) of a circle
62.832 * </span></span></span><span>(9/40) = </span>
<span>
<span>
<span>
14.1372
</span>
</span>
</span>
Source:
http://www.1728.org/radians.htm