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Morgarella [4.7K]
3 years ago
14

2y-x=3/4(-y+1) solve for y

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

(4x + 3)/11

Explanation:

2y -x = 3/4(-y + 1)        Multiply both sides by 4

8y – 4x = 3(-y + 1)        Remove parentheses

8y – 4x = -3y + 3         Add 3y to each side

11y -4x = 3                    Add 4x to each side

11y = 4x + 3                  Divide both sides by 11

y = (4x + 3)/11

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A container is shaped like a triangle prism. Each base of container is an equilateral triangle with the dimensions shown. The co
Aleks04 [339]

Answer:

\text{Lateral surface area of container}=270\text{ cm}^2    

Step-by-step explanation:

Please find the attachment.

We have been given that a container is shaped like a triangle prism. Each base of container is an equilateral triangle with each side 6 cm. The height of container is 15 cm.

To find the lateral surface area of our given container we will use lateral surface area formula of triangular prism.

\text{Lateral surface area of triangular prism}=(a+b+c)*h, where, a, b and c represent base sides of prism and h represents height of the prism.

Upon substituting our given values in above formula we will get,

\text{Lateral surface area of container}=(\text{6 cm+ 6 cm+6 cm})*\text{15 cm}

\text{Lateral surface area of container}=\text{18 cm}*\text{15 cm}

\text{Lateral surface area of container}=270\text{ cm}^2

Therefore, lateral surface area of our given container is 270 square cm.

6 0
3 years ago
Find the perimeter of a triangle with sides 11 inches, 5 inches, and 13 inches. Show your work.
Katarina [22]
To find the perimeter, you add up all the sides. 

11 + 5 + 13 = 29

29 inches is the perimeter. 
7 0
3 years ago
Please help me asap!!!
ololo11 [35]

G should be the correct answer

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4 0
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Rewrite in logarithmic form 19^2 = 361
Aneli [31]

Answer:

  \log_{19}{361}=2

Step-by-step explanation:

We know that taking logarithms performs the transformation ...

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Then for b=19, e=2, x=361, we have

  \boxed{\log_{19}{361}=2}

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23 or 23/1 or  23.0

Hope this helps ;)
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