Answer:
Ethanamine (also known as ethylamine)
Explanation:
The compound that is requested by the question is ethanamine. Its trivial name is ethylamine.
It is a compound that contained the ethyl moiety (CH3CH2-) as well as the amine moiety (-NH2).
Ethanamine has a structure that can easily be determined by the statements in the question.
The structure of ethanamine is shown in the image attached.
To solve this we use the
equation,
<span> M1V1 = M2V2</span>
<span> where M1 is the
concentration of the stock solution, V1 is the volume of the stock solution, M2
is the concentration of the new solution and V2 is its volume.</span>
<span>2.0 M x V1 = 0.50 M x 200 mL</span>
<span>V1 = 50 mL needed</span>
Answer:
V=0.68L
Explanation:
For this question we can use
V1/T1 = V2/T2
where
V1 (initial volume )= 0.75 L
T1 (initial temperature in Kelvin)= 303.15
V2( final volume)= ?
T2 (final temperature in Kelvin)= 273.15
Now we must rearrange the equation to make V2 the subject
V2= (V1/T1) ×T2
V2=(0.75/303.15) ×273.15
V2=0.67577931717
V2= 0.68L
