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Ksju [112]
2 years ago
13

The mass of an electron is about 9.11 × 10 -9 kg., write this whole number​

Chemistry
1 answer:
Pepsi [2]2 years ago
8 0

Answer:0.00000009

Explanation:

9.11 × (1/1000000000)=0.00000009

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CH, +<br> ,<br> 0, → _CO, +<br> Н,0<br> Balance chemical equation
Flura [38]

Answer:

2 CH2 + 3 O2 = 2 CO2 + 2 H2O

Explanation:

This is what I think that you meant by the question listed. When balancing a chemical equation, you want to make sure that there are equal amounts of each element on each side.

Originally, the equation's elements looked like this: 1 C on left & 1 C on right; 2 H on left & 2 H on right; 2 O on left and 3 O on right. Because these are not balanced, you need to add coefficients.

When adding coefficients, you need to make sure that all of the elements stay balanced, not just one that you are trying to fix. I know that some equations are really difficult to balance, and when that is the case, there are equation balancing websites that can help out.

However, what always helps me is making a chart and continuing to keep up with the changes I am making. It is a trial and error process.

6 0
2 years ago
Please solve this for 13 points
Anit [1.1K]

Answer:

sodium

Explanation:

everybody already known its sodium

6 0
3 years ago
What forms the biggest carbon reservoir on Earth?​
guajiro [1.7K]

Answer:

oceans is the answer that I got

4 0
2 years ago
How can I balance this equation? TELL ME HOW you did it and all the steps and you will be the brainliest.
lianna [129]

Answer:

3 CH3CH2OH + 4 H2CrO4 + 6 H2SO4 --> 3 CH3COOH + 2 Cr2(SO4)3 + 13 H2O

Explanation:

To balance, start of with the groups that are common on both sides of the reaction equation;

In this case, these are the SO4 groups treating them as single units;

There are 3 on the right side and 1 on the left side, so we put 3 in front of the H2SO4 to balance this first;

Next, deal with the Cr, there are 2 Cr on the right side and 1 on the other side, so we put a 2 in front of the H2CrO4 to balance that;

Thirdly, we notice the C are already balanced as there are 2 on each side so this is fine;

Lastly, we can deal with the O and H;

Bearing in mind the numbers that are in front of the molecules now from prior balancing, there are 9 O and 16 H on the left side and 3 O and 5 H on the right;

7 H2O on the right side would balance the O, but gives us 18 H, which is 2 too many H;

If we were to put 2 in front of the two organic molecules (the ones with C) on either side, we would balance the O by having 6 H2O, but this gives 2 fewer H than necessary;

In order for the H to balance, we need to have 13/2 (or 6.5) H2O, which means we need 3/2 (or 1.5) in front of each organic molecule;

Since, it is not sensible to have 13/2 water molecules or 3/2 organic molecules, we can just multiply everything by 2;

Thus we end up with:

3 CH3CH2OH + 4 H2CrO4 + 6 H2SO4 --> 3 CH3COOH + 2 Cr2(SO4)3 + 13 H2O

Rules of thumb:

- When there are common chemical groups (e.g. SO4) on both sides of a reaction equation, treat them as single units

- Start of with balancing these common groups

- Thereafter, balance the atoms that appear in only one reactant and one product

- Proceed to balance the atoms that appear in more than one reactant or product

- Typically, you should deal with the O and H last

4 0
3 years ago
SOMEONE HELP ME
nikdorinn [45]
The answer is Sliver reacts with nitric acid to produce a gas.
3 0
3 years ago
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