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Mashcka [7]
3 years ago
15

2 uniones iónicas y 2 covalentes, realizando las estructuras de Lewis correspondiente y averiguar la función del compuesto armad

o en la vida cotidiana.
Chemistry
1 answer:
posledela3 years ago
7 0

Answer:

Cloruro de sodio y fluoruro de sodio.

Dióxido de carbono y monóxido de hidrógeno.

Explicación:

El cloruro de sodio y el fluoruro de sodio son los compuestos que tienen enlaces iónicos. Estos compuestos iónicos se utilizan para diferentes actividades de nuestra vida diaria. El cloruro de sodio se usa para cocinar y el fluoruro de sodio se usa en la pasta de dientes para limpiar nuestros dientes. El dióxido de carbono y el monóxido de hidrógeno son compuestos que tienen enlaces covalentes. El dióxido de carbono se usa en refrescos / refrescos y algunos otros líquidos que se pueden usar en la vida diaria. El monóxido de hidrógeno es el agua pura que bebemos todos los días en nuestra vida diaria y es muy importante para nuestra supervivencia.

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A battery has chemical energy, which can be used to generate thermal and radiant energy in a lightbulb. Which best explains what
WARRIOR [948]

Answer is: The total energy in the system remains the same as the decrease in chemical energy equals the increase in thermal and radiant energy.

The law of conservation of energy states that the total energy of an isolated system remains constant; energy can neither be created nor destroyed; it can only be transformed or transferred from one form (in this example chemical energy) to another (in this example thermal and radiant energy).

Radiant energy or light is the only kind of energy we can see with our eyes. Light have different wavelenght and different color.

Chemical energy - this type of energy is often found in things like batteries or food.

7 0
3 years ago
Read 2 more answers
30 pts! Sodium and water react according to the following equation. If 31.5g of sodium are added to excess water, how many liter
mihalych1998 [28]
First, calculate the number of moles of sodium present with the given mass,

              31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium

It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.

           mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
                  mols of H2 = 0.685 mols H2

Then, at STP, 1 mol of gas = 22.4 L.
                
                 volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
                     volume of H2 = 15.34 L

Answer: 15.34 L
3 0
3 years ago
How is the word theory as it is used in science different from the common use of the word outside of science?
Neko [114]

Answer:A theory is a well-substantiated explanation of an aspect of the natural world that can incorporate laws, hypotheses and facts.

Explanation:

8 0
2 years ago
Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 2.55 g
Charra [1.4K]

Answer:

4.71 g of sodium and 7.25 g of chlorine

Explanation:

<em>Note: The question is incomplete. the complete question is given below:</em>

<em>Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 2.55 g of sodium and 3.93 g of chlorine. Being consistent with the law of constant composition, also called the law of definite proportions or law of definite composition, which set of masses could be the result of the decomposition of the other sample?</em>

<em>4.71 g of sodium and 3.30 g of chlorine</em>

<em>4.71 g of sodium and 7.25 g of chlorine</em>

<em>4.71 g of sodium and 1.31 g of chlorine</em>

<em>4.71 g of sodium and 13.7 g of chlorine</em>

The law of definite proportions states that all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.

This means that irrespective of the source of any sample of a pure chemical compound, the constituents elements are always combined in the same mass ratio.

In the first sample, the mass ratio of Sodium to chlorine is given below:

mass of sodium = 2.55 g

mass of chlorine = 3.93 g

mass ratio; sodium to chlorine = 2.55 / 3.93 = 0.65

From the set of masses give above, we can determine the result of the decomposition of the second sample.

4.71 g of sodium and 3.30 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 3.30 = 1.43

4.71 g of sodium and 7.25 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 7.25 = 0.65

4.71 g of sodium and 1.31 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 1.31 = 3.59

4.71 g of sodium and 13.7 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 13.7 = 0.34

From the results above, the correct set of masses for the second sample is 4.71 g of sodium and 7.25 g of chlorine

3 0
2 years ago
Help with science question
shutvik [7]

Answer:

(4) Inner core. (5) magma. (6) crust (7) Convection current. (8) energy waves

Explanation:

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