<h3>Answer:</h3>
Volume = 11.2 L
<h3>Explanation:</h3>
Step 1: Calculate Moles:
As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.
The relation between Moles, Number of Particles and Avogadro's Number is given as,
Number of Moles = Number of Particles ÷ 6.022 × 10²³
Putting values,
Number of Moles = 3.01× 10²³ Particles ÷ 6.022 × 10²³
Number of Moles = 0.50 Moles
Step 2: Calculate Volume:
As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.
When 1 mole gas occupies 22.4 dm³ at STP then the volume occupied by 0.50 moles of gas is calculated as,
= (22.4 dm³ × 0.50 moles) ÷ 1 mole
= 11.2 dm³ ∴ 1dm³ = 1 L
So,
Volume = 11.2 L
Solution B (17% alcohol) = x ml
Solution A (13% alcohol) = (x-100) ml
0.17x ml alcohol in Solution B
0.13(x-100) ml alcohol in Solution A
0.17x + 0.13(x-100) = 347
0.17x+0.13x-13=347
0.3x = 360
x=360/0.3=3600/3=1200 ml solution B
