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3 years ago

Which statement describes the BEST example of animals avoiding competition?

Chemistry

2 answers:

Svetlanka [38]3 years ago

4 0

Answer:

Explanation:

If the deer leave the forest then they are avoiding compotation

Alex73 [517]3 years ago

3 0

D that’s the answer it avoiding the competition

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After isolating the pure crystals on a Hirsch funnel, wash them with solvent, but they dissolve and disappear into the funnel. W

AlladinOne [14]

Answer:

The pure crystals were soluble in the wash solvent.

Explanation:

The pure crystals on the funnel dissolved because they were soluble in the solvent used for washing. They were carried into the filter flask by the solvent.

3 0

4 years ago

Help, cant get it. Answers in picture

Aleks04 [339]

Answer:17.0

Explanation:

8 0

3 years ago

Calculate the percent composition by mass of the following compounds that are important starting materials for synthetic polymer

notsponge [240]

Answer:

C₃H₄O₂ → 50% C; 5.5 % H; 44.5% O

C₄H₆O₂ → 56 % of C; 7 % of H; 37% of O

C₃H₃N → 68 % of C; 6 % of H; 26 % of N

Explanation:

We determine the molar mass of each compound:

C₃H₄O₂ → 72 g/mol

In 1 mol of acrylic acid (72 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

4 moles of H → 1 g/mol . 4 mol = 4 g of H

2 moles of O → 16g/mol . 2 mol = 32 g of O

Then in 100 g of salt, we may have:

100 . 36 / 72 = 50 % of C

4 . 100 / 72 = 5.5 % of H

32 . 100 / 72 = 44.5 % of O

C₄H₆O₂ → 86 g/mol

In 1 mol of methyl acrylate (86 g), we have:

4 moles of C → 12 g/mol . 4 mol = 48 g of C

6 moles of H → 1 g/mol . 6 mol = 6 g of H

2 moles of O → 16g/mol . 2 mol = 32 g of O

Then in 100 g of salt, we may have:

100 . 48 / 86 = 56 % of C

6 . 100 / 86 = 7 % of H

32 . 100 / 86 = 37 % of O

C₃H₃N → 53 g/mol

In 1 mol of acrylonitrile (53 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

3 moles of H → 1 g/mol . 3 mol = 3 g of H

1 mol of N → 14g/mol . 1 mol = 14 g of N

Then in 100 g of salt, we may have:

100 . 36 / 53 = 68 % of C

3 . 100 / 53 = 6 % of H

14 . 100 / 53 = 26 % of N

3 0

3 years ago

The reaction below is at equilibrium. What would happen if more carbon were

schepotkina [342]

Explanation:

$C_{(s)} + O_{2(g)} \rightleftharpoons CO_{2(g)}$

According to le ch-atelier's principle when a chemical reaction at equilibrium subjected to any stress, then the equilibrium shifts in that direction in which effect of stress is reduced.

When we would add more number of carbon in above reaction then rate of forward reaction will increase to attain the equilibrium again.

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5 0

2 years ago

List the properties of copper, sulfur and copper sulfide?

Y_Kistochka [10]

The answer would be metal

7 0

3 years ago