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denis-greek [22]

3 years ago

13

Which statement describes the BEST example of animals avoiding competition?

2 answers:

Svetlanka [38]3 years ago

4 0

Answer:

D

Explanation:

If the deer leave the forest then they are avoiding compotation

Alex73 [517]3 years ago

3 0

D that’s the answer it avoiding the competition

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devlian [24]

Answer:

<u>The final temperature of both substances at thermal equilibrium is 17.3°C</u>

Explanation:

<u>To calculate the final temperature of both substances at thermal equilibrium -:</u>

First , we calculate the heat of A1 cube as follows -

q= mSΔT

(where q = heat of the cube , m = mass of cube , S= specific heat of cube {0.902j/g°C}, T = Temperature )

Putting the values given in the question ,

$q= 32.5g\times0.902\j/g$ ° $C$ $\times(T_f-45.8$ ° $C)$

$29.315\times(T_f-45.8)J$

Now , calculate the heat of water -

q=mSΔT

Putting values from the question ,

$q=105.3g\times4.18j/g$ ° $C$ $\times (T_f-15.4$ ° $C)$

= $440.154\times(T_f-15.4)J$

Now ,

Heat lost by water A1= Heat gained by water [negative sign about heat lost]

$-29.315\times(T_f-45.8)J$ $=440.154\times(T_f-15.4)J$

$\frac{-(T_f-45.8)J}{T_f-15.4)J} =\frac{440.154}{29.315}=15.0$

$-T_f+45.8$ ° $C=15T_f-231.2$ ° $C$

$(45.8+231.2)$ ° $C$ = $16T_f$

$16T_f=277.03$ ° $C$

$T_f=\frac{277.03}{16}$ = 17.3°C

<u>Therefore , the final temperature of both substances at thermal equilibrium is 17.3°C</u>

<u></u>

3 0

3 years ago

What do plants do that requires Energy?

Kruka [31]

Answer:

Photosynthesis

Explanation:

Photosynthesis uses energy from light to convert water and carbon dioxide molecules into glucose (sugar molecule) and oxygen. The oxygen is released, or “exhaled”, from leaves while the energy contained within glucose molecules is used throughout the plant for growth, flower formation, and fruit development.

7 0

3 years ago

A__________________ is a landform with high elevation and a more or less level surface

earnstyle [38]

A MOUNTAIN RANGE is a landform with high elevation and a more or less level surface

8 0

3 years ago

Read 2 more answers

Chemical bonding in metals is

777dan777 [17]

Answer:

different from ionic or covalent bonding

Explanation:

8 0

3 years ago

Suppose that the mixture in problem 4 is at 15 OC, where the pure vapor pressures are 12.5 mmHg for water and 32.1 mmHg for etha

EleoNora [17]

Answer:

Explanation:

Since we are not given the mole fraction of ethanol and water; we will solve this theoretically.

Using Raoult's Law:

$P_A = (P_o)_A*X_A$

For water:

$(P)w = P_o \times \text{mole fraction of water}$

where $P_o$ of water = 12.5 mmHg

Then, the vapor pressure of water:

$(P)w = 12.5 \ mmHg \times \text{mole fraction of water}$

For ethanol:

$P_E = P_o \times \text {mole fraction of ethanol}$

and the $P_o$ of ethanol = 32.1 mmHg

Then, the vapor pressure of ethanol:

$P_E = 32.1 \ mmHg \times \text {mole fraction of ethanol}$

The total vapor pressure $T_P = P_W + P_E$

The total vapor pressure = $(12.5 \ mmHg \times \text{mole fraction of water}) + (32.1 \ mmHg \times \text {mole fraction of ethanol})$

3 0

3 years ago