Answer:
The correct answer is - 66g.
Explanation:
Given:
molecules of CO2 = 9.03 x 10^23
We know:
1 mole of any substance = 6.02x10^23 molecules. (Avogadro's number)
M (CO2) = 12 + (2x16) = 12 + 32 = 44g
Solution:
The mass of CO2 with 9.03x10^23 molecules would be:
44g of CO2 = 6.02x10^23 molecules.
So, the mass in grams of CO2 (X) = 9.03x10^23 molecules
Xg of CO2 = (44x9.03x10^23)/6.02x10^23 = 66g
Thus, the correct answer would be - 66gm.
The correct answer is: [C]: "Br" {"bromine"} .
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Answer:
24 atm.
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 240 L
Initial pressure (P₁) = 2 atm
Final volume (V₂) = 20 L
Temperature = constant
Final pressure (P₂) =?
The final pressure required, can be obtained by using the Boyle's law equation as shown below:
P₁V₁ = P₂V₂
2 × 240 = P₂ × 20
480 = P₂ × 20
Divide both side by 20
P₂ = 480 / 20
P₂ = 24 atm
Thus, the final pressure required is 24 atm.
Chemical is the answer your looking for.
Assuming that the reactants are:
(NH4)2SO4 (aq) + Ba(NO3)2 (aq)
and the products are:
BaSO4 (s) + 2NH4NO3 (aq),
then you will have to determine which product is insoluble. You should have access to solubility rules to help you determine this.
According to the solubility rules, the following elements are considered insoluble when paired with SO4:
Sr^2+, Ba^2+, Pb^2+, Ag^2+, and Ca^2+
Therefore, the precipitate will be BaSO4 (s).
