Answer:
Mescarinic and Nicotinic
Explanation:
Postganglionic fibers can be present in both sympathetic and parasympathetic divisions, their main difference resides in how in the sympathetic division the postganglionic fibers are adrenergic and use norepinephrine (noradrenalin) as a neurotransmitter, in the parasympathetic division, on the other hand, fibers are cholinergic and use acetylcholine as a neurotransmitter, the<em> postganglionic neurons of sweat glands release acetylcholine for the activation of muscarinic receptors, another kind of receptor for acetylcholine are nicotinic receptors </em>that act as transmembrane sodium/potassium channels, while muscarinic receptors need to act through intracellular proteins.
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33.11 trillion kilometers is equivalent to 3.5 light years
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The balanced equation for the above reaction is as follows;
2C₈H₁₈ + 25O₂ ---> 16CO₂ + 18H₂O
stoichiometry of octane to CO₂ is 2:16
number of C₈H₁₈ moles reacted - 191.6 g / 114 g/mol = 1.68 mol
when 2 mol of octane reacts it forms 16 mol of CO₂
therefore when 1.68 mol of octane reacts - it forms 16/2 x 1.68 = 13.45 mol of CO₂
number of CO₂ moles formed - 13.45 mol
therefore mass of CO₂ formed - 13.45 mol x 44 g/mol = 591.8 g
mass of CO₂ formed is 591.8 g
Answer: (C) Dissolution is the process by which a solute form a solution in a solvent.
Explanation: Dissolution can be described as the process by which a solute dissolves in a solvent to give a solvent.
The solute may be a solid, liquid or gas and solvent is usually a liquid but can also be liquid, gas or supercritical fluid. The most common solvent is water and it is referred to as the universal solvent.
Example are:
1.Stirring of sugar in water.
In this case the solute is the sugar and the solvent is water.
2.Organic substances dissolves readily in solvent like kerosene and benzene and they are known as non-polar solvent while the organic substances are the solute
If 10 g of NaOH is diluted to 500 ml with water then the concentration expressed in percent is 0.5 mol/L .
Calculation ,
Given mass in gram = 10 g
Number of moles = given mass /molar mass = 10 g / 40 g/mol = 0.25mole
Given volume in ml = 500 ml
Given volume in liter = 0.5 L
Putting the value of mass and volume in equation i we get concentration expressed in percent .
C = number of moles ×100/ volume in liter = 0.25mole ×100/ 0.5 L
C = 0.5 mol/L
Concentration of solution in terms of percentage can be expressed in two ways
1) percentage by mass
2) percentage by volume
Hence, for liquid solutions, concentration is expressed in terms of percentage by volume.
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