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marishachu [46]
3 years ago
6

Which expression is not equal to the number 0?

Mathematics
2 answers:
saw5 [17]3 years ago
6 0

Answer:

It's 6 - (-6)

Step-by-step explanation:

Two negatives make a positive so instead of subtracting you're now adding.

tangare [24]3 years ago
3 0
2) 6-(-6)

hope this helps youu
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Kevin can travel 22 1/2 miles in 1/3 hour. What is his average speed in miles per hour? A.65 mph B.65.7 mph C.68 mph D.70 mph
mojhsa [17]

To find the answer, multiply 22 1/2 by 3.

22 1/2 x 3 = 67 1/2

This can round up to 68

The answer is C. 68 mph

If you have any further questions feel free to ask.

Hope this helps.

7 0
4 years ago
What is 8 to the 7th power
saveliy_v [14]
8 x 8 x 8 x 8 x 8 x 8 x 8
64 x 64 x 64 x 8
4096 x 512
=2 097 152
6 0
3 years ago
Fully answer BOTH questions a and b below.
Setler [38]
A. 540 is 60% of 900 so 900 people were surveyed.
60/100 • x= 540
Multiply both sides by 100
Then divide both sides by 60

B. If you subtract 900-540 your answer will be 360. 360 people preferred running.
6 0
3 years ago
Trying to find the x
Lapatulllka [165]

Step-by-step explanation:

why .....................

7 0
2 years ago
What is the vertex of the parabola whose equation is y = (x + 1)2 + 3? (-1, -3) (-1, 3) (1, 3)
White raven [17]
Algebra:
A standard parabola is y = x^2. Its vertex is at (0,0)
You can change the position (or vertex) of the parabola.
To move a parabola across the x-axis, you can add or subtract a number from x WITHIN brackets of the ^2
eg. (x + 1)^2 will move the parabola across the x-axis. It will move is one unit to the LEFT (as the sign is opposite to the direction it moves ie. The sign it + but you move the whole parabola in the -ve direction).
Adding or subtracting a number from x OUTSIDE of the ^2 moves the parabola up or down the y-axis
eg. x^2 + 3 will move the parabola UP 3 units (the sign is the same as the direction it moves when the added/subtracted number is outside of the ^2 ie. the sign is positive so the parabola moves up in the positive direction)

From this, we can conclude that because (x + 1)^2 + 3, the vertex will be where x = -1 and where y = 3

Vertex : (-1,3)



Calculus:
f(x) = (x + 1)^2 + 3 = x^2 + 2x + 1 + 3 = x^2 + 2x + 4
Expanding the formular to make it easier to differentiate

f'(x) = 2x + 2
Differentiating (finding the formular the the gradiet of the parabola)

0 = 2x + 2
When the gradient is equal to zero, it must be the vertex

-2 = 2x
-2/2 = x
x = -1
Solve to give the x value at the vertex

f(x) = (x + 1)^2 + 3
= (-1 + 1)^2 + 3
Substitute x = -1 into original equatiom to find y value at the vertex

= (0)^2 + 3
= 0 + 3
= 3
Solve for y

Vertex : (-1,3)


6 0
3 years ago
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