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Elanso [62]
3 years ago
5

What is 8 to the 7th power

Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0
8 x 8 x 8 x 8 x 8 x 8 x 8
64 x 64 x 64 x 8
4096 x 512
=2 097 152
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4 martians, 3 plutonians and 5 jupiterians are to be seated in a row at an interplanetary conference. How many seating arrangeme
Rudik [331]

we are given

martians =4

plutonians =3

jupiterians=5

so, total number of seats =4+3+5=12

number of seating arrangement for martians is 4!

number of seating arrangement for plutonians is 3!

number of seating arrangement for jupiterians is 5!

total number of seating arrangement is 12!

so, we get

possible seating arrangements are

=\frac{12!}{4!3!5!}

=27720.............Answer

8 0
3 years ago
This was the question it got deleted I just need 1,2,5
scoundrel [369]

Answer:

1. The volume of the cylinder is 263 cm^{3}.

2. The volume of the cylinder is 12 m^{3}.

3. The volume of the cylinder is 3165.1 cm^{3}.

4. The radius of the cylinder is 3.6 cm.

5a. Area of the base is 50.2 cm^{2}.

5b. The curved surface area of the pencil holder is 351.7 cm^{2}.

5c. The surface are of the pencil holder is 452.2 cm^{2}.

Step-by-step explanation:

1. The given shape is a cylinder, so that;

volume of a cylinder = \pir^{2}h

                                  = 3.14 x (3.8)^{2} x 5.8

                                  = 262.98128

The volume of the cylinder is 263 cm^{3}.

2. This is also a cylinder, but with a given diameter.

radius = \frac{diameter}{2}

          = \frac{1.2}{2} = 0.6 m

volume of a cylinder = \pir^{2}h

                                  = 3.14 x (0.6)^{2} x 10.6

                                  = 11.98224

The volume of the cylinder is 12 m^{3}.

3. volume of a cylinder = \pir^{2}h

                                      = 3.14 x 6^{2} x 28

                                      = 3165.12

The volume of the cylinder is 3165.1 cm^{3}.

4. volume of a cylinder = \pir^{2}h

239 = 3.14 x r^{2} x 6

239 = 18.84 r^{2}

r^{2} = \frac{239}{18.84}

   = 12.6858

r = \sqrt{12.6858}

 = 3.5617

The radius of the cylinder is 3.6 cm.

5. Area of the base = \pir^{2}

radius = \frac{diameter}{2}

           = \frac{8}{2} = 4 cm

Area of the base = 3.14 x 4^{2}

                            = 50.24

Area of the base is 50.2 cm^{2}.

5b. Area of the curved surface of the pencil holder = 2\pirh

                                                                    = 2 x 3.14 x 4 x 14

                                                                     = 351.68

The curved surface area of the pencil holder is 351.7 cm^{2}.

5c. Surface area of the pencil holder = 2\pirh + 2\pir^{2}

                               = 2\pir(h + r)

                                = 2 x 3.14 x 4 (14 + 4)

                                = 452.16

The surface are of the pencil holder is 452.2 cm^{2}.

7 0
2 years ago
In previous months, you ordered 80 boxes of pens per month. This month, you want to decrease the number of boxes of pens you ord
Lapatulllka [165]
80(0.40)=32
80-32=48 boxes of pens
3 0
3 years ago
Read 2 more answers
Rose is drawing a portrait for her art class. She is using a sheet of paper what is 6 inches wide and 12 inches long. What is th
rosijanka [135]

Answer:

0.5 ft^2

Step-by-step explanation:

The area in square inches is (6 in )(12 in) = 72 in^2.

Recall that 1 ft^2 = 144 in^2.

Then

  72 in^2         1 ft^2

--------------- * --------------- = 0.5 ft^2

         1           144 in^2

6 0
3 years ago
If <img src="https://tex.z-dn.net/?f=t_n" id="TexFormula1" title="t_n" alt="t_n" align="absmiddle" class="latex-formula"> = 11n−
4vir4ik [10]

\displaystyle\bf\\t_n=11n-6\\\\t_1=11\cdot1-6=11-6=\boxed{\bf5}\\\\t_{10}=11\cdot10-6=110-6=\boxed{\bf104}\\\\t_{n+1}-t_n=11(n+1)-6-(11\cdot n-6)=11n+11-6-11n+6=\boxed{\bf11}

4 0
3 years ago
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