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Andreyy89
3 years ago
9

Question 2 (1 point)

Chemistry
1 answer:
gregori [183]3 years ago
5 0

Answer:

John Dalton

Explanation:

Both John Dalton and Democritus thought that the atom was an indivisible sphere until J.J. Thompson came out with the plum pudding model. Hope I helped!

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An aqueous potassium iodate (KIO3) solution is made by dissolving 553 grams of KIO3 in sufficient water so that the final volume
liberstina [14]

Answer:

M KIO3 = 1.254 mol/L

Explanation:

  • molarity (M) [=] mol/L

∴ w KIO3 = 553 g

∴ mm KIO3 = 214.001 g/mol

∴ volumen sln = 2.10 L

⇒ mol KIO3 = (553 g)×(mol/210.001 g) = 2.633 mol

⇒ M KIO3 = (2.633 mol KIO3 / (2.10 L sln)

⇒ M KIO3 = 1.254 mol/L

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3 years ago
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Amy watches as her teacher adds a small
inysia [295]

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Explanation:

A) bubbles show hydrogen gas escaping

B) the water reacted with sodium to form an alkaline solution

6 0
3 years ago
29.5 g of mercury is heated from 32°C to 161°C, and absorbs 499.2 joules of heat in the process. Calculate the specific heat cap
Finger [1]

Answer:

c = 0.13 j/ g.°C

Explanation:

Given data:

Mass of mercury = 29.5 g

Initial temperature = 32°C

Final temperature = 161°C

Heat absorbed = 499.2 j

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m.c. ΔT

ΔT  = T2 - T1

ΔT  = 161°C - 32°C

ΔT  = 129 °C

Q = m.c. ΔT

c = Q / m. ΔT

c = 499.2 j / 29.5 g. 129 °C

c =  499.2 j / 3805.5 g. °C

c = 0.13 j/ g.°C

5 0
3 years ago
If the starting volume of a hot air balloon is 55,500 m3and the initial temperature is 21 °C, what is the temperature inside the
Dmitry_Shevchenko [17]

Answer:

T₂ = 392 K

Explanation:

Given that,

Initial volume of the hot air balloon, V₁ = 55500 m³

Initial temperature, T₁ = 21°C = 294 K

Final volume, V₂ = 74000 m³

We need to find the final temperature inside the balloon. The relation between the temperature and volume is given by charles law i.e.

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Where

T₂ is the final temperature

So,

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{294\times 74000 }{55500 }\\\\T_2=392\ K

So, the new temperature is 392 K.

8 0
2 years ago
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