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mars1129 [50]
2 years ago
11

The electron configuration of an element is 1s22s22p63s1.

Chemistry
1 answer:
k0ka [10]2 years ago
6 0

The element is Sodium with an atomic number of 11 and electrovalent bonding takes place when it comes near an atom having seven valence electrons.

<h3>What is Electrovalent bonding?</h3>

This is also referred to as ionic bonding and involves the transfer of atoms of an element to another.

In order for both of them to achieve a stable octet configuration, sodium donates one atom to the element seven valence electrons.

Read more about Electrovalent bonding here brainly.com/question/1979431

#SPJ1

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3 years ago
The table shows the amount of radioactive element remaining in a sample over a period of time.
Assoli18 [71]

It would take 147 hours for 320 g of the sample to decay to 2.5 grams from the information provided.

Radioactivity refers to the decay of a nucleus leading to the spontaneous emission of radiation. The half life of a radioactive nucleus refers to the time required for the nucleus to decay to half of its initial amount.

Looking at the table, we can see that the initial mass of radioactive material present is 186 grams, within 21 hours, the radioactive substance decayed to half of its initial mass (93 g). Hence, the half life is 21 hours.

Using the formula;

k = 0.693/t1/2

k = 0.693/21 hours = 0.033 hr-1

Using;

N=Noe^-kt

N = mass of radioactive sample at time t

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t = time taken

Substituting values;

2.5/320= e^- 0.033 t

0.0078 = e^- 0.033 t

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t = ln (0.0078)/-0.033

t = 147 hours

Learn more: brainly.com/question/6111443

7 0
2 years ago
What inference can be drawn from the graph?
defon

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i think its C

Explanation:

7 0
2 years ago
Câu 36: _VD _Hình lập phương có thể tích là 1253 thì diện tích đáy là:
Gnesinka [82]

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5 0
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Read 2 more answers
At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1·M−1s−1 : →2SO3g+2SO2gO2g Suppo
RoseWind [281]

Answer:

[SO_3]=0.25M

Explanation:

Hello there!

In this case, since the integrated rate law for a second-order reaction is:

[SO_3]=\frac{[SO_3]_0}{1+kt[SO_3]_0}

Thus, we plug in the initial concentration, rate constant and elapsed time to obtain:

[SO_3]=\frac{1.44M}{1+14.1M^{-1}s^{-1}*0.240s*1.44M}\\\\

[SO_3]=0.25M

Best regards!

4 0
3 years ago
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