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Dimas [21]
3 years ago
6

PLEASE HELP ME!

Chemistry
1 answer:
n200080 [17]3 years ago
5 0

Answer:

"Calculate" (and any subsequent words) was ignored because we limit queries to 32 words.

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Joaq...
MrRa [10]

Answer:

all the statements are true of chemical changes

3 0
2 years ago
What can be said of a closed system when an exothermic reaction proceeds in an aqueous solution?
lyudmila [28]
An exothermic reaction is a type of reaction that dissipates heat as the reaction proceeds. This would mean that in a closed system, when a reaction proceeds and is endothermic, the temperature of the solution  or the system would increase so as to maintain the equilibrium with the whole system.
8 0
2 years ago
Do atoms lend and borrow electrons from inner shells
zaharov [31]
False. They don't borrow electrons at all. They already have their respective electron affinities. This is called as electronegativity, and it's an occurence where it already has its own from its actual structure. It never borrows any electrons at all.
4 0
3 years ago
A solution...
steposvetlana [31]

Answer:

A

Explanation:

8 0
3 years ago
Read 2 more answers
What is the density of 0.50 grams of gaseous carbon stored under 1.5 atm of pressure at a temperature of -20.0 C?
Colt1911 [192]

Answer: The density of 0.50 grams of gaseous carbon stored under 1.50 atm of pressure at a temperature of -20.0 °C is 0.867 g/L.

Explanation:

  • d = m/V, where d is the density, m is the mass and V is the volume.
  • We have the mass m = 0.50 g, so we must get the volume V.
  • To get the volume of a gas, we apply the general gas law PV = nRT

P is the pressure in atm (P = 1.5 atm)

V is the volume in L (V = ??? L)

n is the number of moles in mole, n = m/Atomic mass, n = 0.50/12.0 = 0.416 mole.

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature in K (T(K) = T(°C) + 273 = -20.0 + 273 = 253 K).

  • Then, V = nRT/P = (0.416 mol)(0.082 L.atm/mol.K)(253 K) / (1.5 atm) = 0.576 L.
  • Now, we can obtain the density; d = m/V = (0.50 g) / (0.576 L) = 0.867 g/L.
6 0
3 years ago
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