The slope is rise over run, how many times you go up (or if down it'd be a negative) and over.
The y-intercept is what point on the y axis the line passes through
Answer: f(x) = 1^(x + 1)
Step-by-step explanation:
we have that h(x) = 1^x
and h(x) = f(g(x))
This mean that we are evaluating the function f(y) in the point y = g(x)
where g(x) = x - 1
then:
f(g(x) = f(x - 1) = h(x) = 1^x
then we should have that:
f(x) = 1^(x + 1)
then:
f(x - 1) = 1^(x - 1 + 1) = 1^x
Step-by-step explanation:
Given :-
The length of the garden 8m greater than 2 times the width.
Area of the garden is 280 m²
Let us consider the length as x and width as y.
Sp, we can day length as :-
x = 8 + 2y ---(1)
Now, we know that:-
Area of Rectangle = Length × Breadth
280 = x * y
We can replace the value of x now,
280 = y × ( 8 + 2y)
280 = 8y + 2y²
2y² + 8y - 280 = 0
y² + 4y - 140 = 0
Factorise it.
(y -10)(y + 14)
Cancelling -ve value, we get the width as 10 metres.
<u>Hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>:</u><u>)</u>
Answer: y = 3x/4 + 22
Step-by-step explanation:
The equation of line l is -3y + 4x = 9
-3y + 4x = 9
3y = 4x -9
y = (4x -9)/3= 4x/3 - 3
From the slope-intercept equation,
y = mx +c
Where m= slope
Comparing both equations, we have
m = 4/3
If the new line that parallel to line l, that means they have the same slope
So, slope if new line is 3/4.
Points =(-12, 6)
From y = mx + c
x = -12,y = 6
6= 4/3 × -12 + c
6 = -16 + c
c = 6 + 16 = 22
Therefore
The equation of the line that is parallel to line l and passes through the point (-12,6) ,
y = 3x/4 + 22
