Given:
Two vectors (u) and (w) and the angle between them θ
![\begin{gathered} |u|=50 \\ |w|=12 \\ \theta=35\degree \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%7Cu%7C%3D50%20%5C%5C%20%7Cw%7C%3D12%20%5C%5C%20%5Ctheta%3D35%5Cdegree%20%5Cend%7Bgathered%7D)
the sketch of the vectors will be as shown in the following figure:
As shown, the resultant vector is the blue line segment
The vector R has a magnitude = 60.22
And the angle between u and R = 5.56°
Answer: Choice A)
![H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7BSA%7D%7B2%28L%2BW%29%7D%20-%20%5Cfrac%7BLW%7D%7BL%2BW%7D%5C%5C%5C%5C)
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Work Shown:
![SA = 2(LW + LH + HW)\\\\2(LW + LH + HW) = SA\\\\LW + LH + HW = \frac{SA}{2}\\\\LH + HW = \frac{SA}{2} - LW\\\\H(L + W) = \frac{SA}{2} - LW\\\\H = \frac{\frac{SA}{2} - LW}{(L + W)}\\\\H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\](https://tex.z-dn.net/?f=SA%20%3D%202%28LW%20%2B%20LH%20%2B%20HW%29%5C%5C%5C%5C2%28LW%20%2B%20LH%20%2B%20HW%29%20%3D%20SA%5C%5C%5C%5CLW%20%2B%20LH%20%2B%20HW%20%3D%20%5Cfrac%7BSA%7D%7B2%7D%5C%5C%5C%5CLH%20%2B%20HW%20%3D%20%5Cfrac%7BSA%7D%7B2%7D%20-%20LW%5C%5C%5C%5CH%28L%20%2B%20W%29%20%3D%20%5Cfrac%7BSA%7D%7B2%7D%20-%20LW%5C%5C%5C%5CH%20%3D%20%5Cfrac%7B%5Cfrac%7BSA%7D%7B2%7D%20-%20LW%7D%7B%28L%20%2B%20W%29%7D%5C%5C%5C%5CH%20%3D%20%5Cfrac%7BSA%7D%7B2%28L%2BW%29%7D%20-%20%5Cfrac%7BLW%7D%7BL%2BW%7D%5C%5C%5C%5C)
This is not the only way to solve for H.
Again using the Pythagorean Theorem:
h^2=x^2+y^2, where h is the hypotenuse of a right triangle and x and y are the side lengths. You are given that the hypotenuse is 34 ft and the base side is 16ft. Let h=34, x=16, and y=height, then you have:
34^2=16^2+y^2
y^2=34^2-16^2
y^2=1156-256
y^2=900
y=√900
y=30 ft
So the ladder will reach a spot 30 feet high on the building.
Answer:
The exact value of tan 300° is ⏩ - √3
Hope it will help :)❤
Answer:
B) 44
Step-by-step explanation:
Let's start with the triangles. Normally, when dealing with triangles, you would use the formula (B*H*1/2), but since there's two identical triangles, we can just do (B*H) and get the area for both:
2.5*5.5=<u>13.75</u>
Then to solve for the square, it is also (B*H):
5.5*5.5=<u>30.25</u>
At this point, to solve for the total area, you just add the areas together:
13.75+30.25=<u>44</u>
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Hope this helps!